题意:移掉长度为L的区间后剩余数组的LIS
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<math.h>
#include<set>
#include<map>
#include<stack>
#include<vector>
#include<queue>
using namespace std;
typedef unsigned long long ll;
const int N=1e5+10;
const int INF=0x3f3f3f3f;
int a[N],st[N],tot;
int n,m;
int f[N],g[N];
void solve(){
if(n==m){
puts("0");return;
}
memset(st,0x3f,(n+1)*sizeof(st[0]));
tot=0;f[n+1]=0;st[0]=-INF;
a[n+1]=INF;
for(int i=n;i>=1;i--){
if(-a[i]>st[tot]){
st[++tot]=-a[i];
f[i]=tot;
continue;
}
int cnt=lower_bound(st,st+1+tot,-a[i])-st;
st[cnt]=min(st[cnt],-a[i]);
f[i]=cnt;
}
//for(int i=1;i<=n;i++)printf("%d,",f[i]);
memset(st,0x3f,(n+1)*sizeof(st[0]));st[0]=-INF;
int ans=1,temp,l,r;
for(int i=1;i+m<=n+1;i++){
r=f[i+m];l=lower_bound(st,st+n,a[i+m])-st;
ans=max(ans,l+r-1);
int cnt=lower_bound(st,st+n,a[i])-st;
st[cnt]=min(st[cnt],a[i]);
}
printf("%d\n",ans);
}
void work(){
int T;
int tt=1;
scanf("%d",&T);
int D;
while(T--){
scanf("%d%d",&n,&m);
printf("Case #%d: ",tt++);
for(int i=1;i<=n;i++)
scanf("%d",&a[i]);
solve();
}
}
int main(){
//freopen("data_in.txt","r",stdin);
work();
return 0;
}