60、Kernel Synchronization and Lock Debugging

Kernel Synchronization and Lock Debugging

1. Per - CPU Variables in the Kernel

1.1 Controlling Live CPUs at Runtime

In a virtual machine, if you have multiple CPUs but want only a subset to be “live” at runtime, you can pass the maxcpus=n parameter to the VM’s kernel at boot. You can check if this parameter is set by looking at /proc/cmdline . For example:

$ cat /proc/cmdline
BOOT_IMAGE=/boot/vmlinuz-5.4.0-llkd-dbg root=UUID=1c4<...> ro console=ttyS0,115200n8 console=tty0  quiet splash 3 maxcpus=2

Here, we can see that the maxcpus=2 parameter is set, meaning only two CPUs will be active at runtime.

1.2 Per - CPU Variable Usage in th

The producer-consumer problem is a classic synchronization problem in computer science. It involves two processes, a producer and a consumer, who share a common buffer. The producer puts items into the buffer, while the consumer takes items out of the buffer. The problem arises when the buffer is full, and the producer needs to wait until the consumer has consumed some items before it can add more, and when the buffer is empty, and the consumer needs to wait until the producer has produced some items before it can consume them. One way to solve this problem is by using semaphores or locks. Semaphores are integer variables that can be used to control access to shared resources. They have two fundamental operations, wait() and signal(). The wait() operation decrements the semaphore value, and if it is negative, it blocks the process until the value becomes positive. The signal() operation increments the semaphore value and unblocks any waiting processes. A solution using semaphores for the producer-consumer problem involves two semaphores, empty and full, and a mutex lock. The empty semaphore is initialized to the size of the buffer, while the full semaphore is initialized to 0. The mutex lock is used to ensure that only one process can access the buffer at a time. The producer process waits on the empty semaphore, acquires the mutex lock, adds an item to the buffer, releases the mutex lock, and signals the full semaphore. The consumer process waits on the full semaphore, acquires the mutex lock, removes an item from the buffer, releases the mutex lock, and signals the empty semaphore. Here is some sample pseudocode: ``` // Shared variables int buffer[N]; int count = 0; // number of items in buffer int in = 0; // index for producer to put items int out = 0; // index for consumer to take items // Semaphores Semaphore empty = N; Semaphore full = 0; // Mutex lock Lock mutex; // Producer code while (true) { produce_item(); empty.wait(); mutex.acquire(); buffer[in] = item; in = (in + 1) % N; count++; mutex.release(); full.signal(); } // Consumer code while (true) { full.wait(); mutex.acquire(); item = buffer[out]; out = (out + 1) % N; count--; mutex.release(); empty.signal(); consume_item(item); } ``` This solution ensures that the producer and consumer processes do not access the buffer at the same time, and that the buffer is not overfilled or underfilled.
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