链表的常见操作

链表的常见操作

 

  链表是数据结构的重要内容,在计算机程序中应用广泛,同时也是各公司笔试题目的重点。

  以下简单实现了链表的一些操作,包括创建、增加节点、删除节点、单链表逆置、合并有序链表等。

 

一、链表创建

  链表主要有三种形式,包括单链表、双链表和循环链表。

  单链表每个节点只包含一个后驱指针,双链表节点同时包含一个前驱指针和一个后驱指针,循环链表的尾节点的后驱指向头节点。

  代码如下:

 


   
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 单链表节点结构 */ typedef struct NodeType { char elem; NodeType * next; }Node; /* 双链表节点结构 */ typedef struct DNodeType { char elem; DNodeType * next; DNodeType * prev; }DNode;

 

 

 

创建单链表

     
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 创建链表 */ Node * CreateList(Node * head) { if (NULL == head) // 分配头节点空间 head = (Node * )malloc( sizeof (Node)), head -> next = NULL; Node * current = head , * temp; char ch; while ( 1 ) { cout << " \n input elem: " ; cin >> ch; if ( ' # ' == ch) /* #结束输入 */ break ; temp = (Node * ) malloc ( sizeof (Node) ); temp -> elem = ch; temp -> next = NULL; current -> next = temp; /* 当前节点的后驱指向新节点 */ current = temp; /* 当前节点为链表尾节点 */ } return head; }

 

创建双链表

     
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 创建双链表 */ DNode * DoubleList(DNode * head) { if (NULL == head) // 分配头节点空间 head = (DNode * )malloc( sizeof (DNode)) , head -> prev = NULL , head -> next = NULL; DNode * current = head , * temp; char ch; while ( 1 ) { cout << " \n input elem: " ; cin >> ch; if ( ' # ' == ch) /* #结束输入 */ break ; temp = (DNode * ) malloc ( sizeof (DNode) ); temp -> elem = ch; temp -> next = NULL; current -> next = temp; /* 当前节点的后驱指向新节点 */ temp -> prev = current; /* 新节点的前驱指向当前节点 */ current = temp; /* 当前节点为链表尾节点 */ } return head; }

 

创建循环链表

     
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 创建循环链表 */ Node * CycleList(Node * head) { if (NULL == head) /* 分配头节点空间 */ head = (Node * )malloc( sizeof (Node)),head -> next = NULL; Node * current = head , * temp; char ch; while ( 1 ) { cout << " \n input elem: " ; cin >> ch; if ( ' # ' == ch) /* #结束输入 */ break ; temp = (Node * ) malloc ( sizeof (Node) ); temp -> elem = ch; temp -> next = NULL; current -> next = temp; /* 当前节点的后驱指向新节点 */ current = temp; /* 当前节点为链表尾节点 */ } current -> next = head; /* 尾节点指向头节点 */ return head; }

 

二、链表操作

  包括单链表的增加节点、删除节点、输出链表等

添加节点

    
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 插入节点 */ Node * InsertNode(Node * head , char elem) { if ( NULL == head || NULL == elem ) return head; Node * current = head -> next; /* 当前节点 */ Node * prev = head; /* 前驱节点 */ Node * temp; /* 过渡节点 */ while (current) /* 移动至尾节点 */ { prev = current; current = current -> next; } temp = (Node * ) malloc( sizeof (Node) ); temp -> elem = elem; temp -> next = NULL; prev -> next = temp; /* 尾节点的后驱指向新节点 */ return head; }

 

删除节点

    
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 删除节点 */ Node * DeleteNode(Node * head, char elem) { if (NULL == head || NULL == elem) return head; if (NULL == head -> next) return head; Node * prev, * current; prev = head; current = head -> next; while (current) { if (current -> elem == elem) /* 匹配节点元素 */ { prev -> next = current -> next; /* 前驱节点的后驱指向当前节点的下一个节点 */ free(current); /* 释放当前节点 */ return head; } prev = current; current = current -> next; /* 移动至下一个节点 */ } return head; }

 

输出链表

    
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 输出链表 */ void PrintList(Node * head) { Node * current = head -> next; cout << " \n List are: " ; while (NULL != current) { if (NULL != current -> elem) cout << setw( 5 ) << current -> elem; current = current -> next; } cout << " \n " ; }

 

三、单链表逆置
  单链表逆置在各公司的笔试题中比较常见,以下是其中一种实现。
  算法描述:将链表中每一个节点插入到头结点之后。
  
  代码如下:
单链表逆置

     
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 单链表逆置 */ Node * ReverseList(Node * head) { if (NULL == head) return head; if (NULL == head -> next) return head; if (NULL == head -> next -> next) return head; Node * curr = head -> next; /* 当前节点 */ head -> next = NULL; Node * temp; while (curr) { temp = curr -> next; /* 暂存下一个节点 */ /* 把当前节点插入到head节点后 */ curr -> next = head -> next; head -> next = curr; curr = temp; /* 移动至下一个节点 */ } return head; }

 

四、求单链表中间节点

  在笔试题中比较常见,通常题目描述是:给出一个单链表,不知道节点N的值,怎样只遍历一次就可以求出中间节点。
  算法描述:设立两个指针p1,p2,p1每次移动1个节点位置,p2每次移动2个节点位置,当p2移动到尾节点时,p1指向中间节点。
  
  代码如下:

求中间节点

    
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 求中间节点 */ Node * MiddleNode(Node * head) { if (NULL == head) return head; if (NULL == head -> next) return head -> next; Node * p1, * p2; p1 = head; p2 = head; while (p2 -> next) { /* p2节点移动2个节点位置 */ p2 = p2 -> next; if (p2 -> next) /* 判断p2后驱节点是否存在,存在则再移动一次 */ p2 = p2 -> next; /* p1节点移动1个节点位置 */ p1 = p1 -> next; } return p1; }

 

五、合并有序单链表
  问题描述:合并2个有序单链表,合并后的链表也是排好序的。
  算法描述:对链表A中的每一个节点元素,查找其在链表B中的插入位置,并在B中插入该元素。
  代码如下:
合并有序单链表

      
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 合并有序单链表 */ Node * MergeList(Node * h1,Node * h2) { if (NULL == h1 || NULL == h2) return h1; if (NULL == h1 -> next ) return h2; if (NULL == h2 -> next) return h1; Node * curr1, * curr2, * prev1, * temp; prev1 = h1; /* 链表1的前驱节点 */ curr1 = h1 -> next; /* 链表1的当前节点 */ curr2 = h2 -> next; /* 链表2的当前节点 */ temp = h2; while (curr2) { while (curr1 && curr1 -> elem < curr2 -> elem) /* 链表1指针移动至大或等于链表2当前元素的位置 */ prev1 = curr1,curr1 = curr1 -> next; /* 在链表1中插入链表2的当前元素 */ temp = curr2 -> next; /* 暂存链表2的下一个节点 */ prev1 -> next = curr2; curr2 -> next = curr1; /* 链表1移动至新节点 */ curr1 = curr2; /* 链表2移动至下一个节点 */ curr2 = temp; } return h1; }

 

六、判断链表是否有环

  判断链表是否有环即是判断链表是否为循环链表,算法较为简单,一次遍历判断尾指针是否指向头指针即可。

  代码如下:

 

判断链表是否有环

     
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* 判断链表是否有环(循环链表) */ bool IsCycleList(Node * head) { if (NULL == head) return false ; if (NULL == head -> next) return false ; Node * current = head -> next; while (current) { if (head == current -> next) return true ; current = current -> next; } return false ; }

 


 

七、总结
  以上实现了链表的一些常见操作,源文件LinkList.cpp全部代码如下: 
LinkList.cpp

     
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> /* * 作者: 达闻东 * 修改日期: 2010-04-28 17:10 * 描述: 实现链表的常见操作 * */ #include < iostream > #include < iomanip > using namespace std; /* 单链表节点结构 */ typedef struct NodeType { char elem; NodeType * next; }Node; /* 双链表节点结构 */ typedef struct DNodeType { char elem; DNodeType * next; DNodeType * prev; }DNode; /* ============================================================================= */ /* 创建链表 */ Node * CreateList(Node * head) { if (NULL == head) // 分配头节点空间 head = (Node * )malloc( sizeof (Node)), head -> next = NULL; Node * current = head , * temp; char ch; while ( 1 ) { cout << " \n input elem: " ; cin >> ch; if ( ' # ' == ch) /* #结束输入 */ break ; temp = (Node * ) malloc ( sizeof (Node) ); temp -> elem = ch; temp -> next = NULL; current -> next = temp; /* 当前节点的后驱指向新节点 */ current = temp; /* 当前节点为链表尾节点 */ } return head; } /* ============================================================================= */ /* 输出链表 */ void PrintList(Node * head) { Node * current = head -> next; cout << " \n List are: " ; while (NULL != current) { if (NULL != current -> elem) cout << setw( 5 ) << current -> elem; current = current -> next; } cout << " \n " ; } /* ============================================================================= */ /* 插入节点 */ Node * InsertNode(Node * head , char elem) { if ( NULL == head || NULL == elem ) return head; Node * current = head -> next; /* 当前节点 */ Node * prev = head; /* 前驱节点 */ Node * temp; /* 过渡节点 */ while (current) /* 移动至尾节点 */ { prev = current; current = current -> next; } temp = (Node * ) malloc( sizeof (Node) ); temp -> elem = elem; temp -> next = NULL; prev -> next = temp; /* 尾节点的后驱指向新节点 */ return head; } /* ============================================================================= */ /* 删除节点 */ Node * DeleteNode(Node * head, char elem) { if (NULL == head || NULL == elem) return head; if (NULL == head -> next) return head; Node * prev, * current; prev = head; current = head -> next; while (current) { if (current -> elem == elem) /* 匹配节点元素 */ { prev -> next = current -> next; /* 前驱节点的后驱指向当前节点的下一个节点 */ free(current); /* 释放当前节点 */ return head; } prev = current; current = current -> next; /* 移动至下一个节点 */ } return head; } /* ============================================================================= */ /* 单链表逆置 */ Node * ReverseList(Node * head) { if (NULL == head) return head; if (NULL ==
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