2016 Asia Regional Dalian Online 1006

题目链接：

http://acm.split.hdu.edu.cn/showproblem.php?pid=5873

题意：有n个球队，按单向循环赛制比赛，已知各个队的得分，判断该得分是否可能产生。

Problem Description

A mysterious country will hold a football world championships---Abnormal Cup, attracting football teams and fans from all around the world. This country is so mysterious that none of the information of the games will be open to the public till the end of all the matches. And finally only the score of each team will be announced. 
  
  At the first phase of the championships, teams are divided into M groups using the single round robin rule where one and only one game will be played between each pair of teams within each group. The winner of a game scores 2 points, the loser scores 0, when the game is tied both score 1 point. The schedule of these games are unknown, only the scores of each team in each group are available.
  
  When those games finished, some insider revealed that there were some false scores in some groups. This has aroused great concern among the pubic, so the the Association of Credit Management (ACM) asks you to judge which groups‘ scores must be false.

 

 

Input

Multiple test cases, process till end of the input.
  
  For each case, the first line contains a positive integers M, which is the number of groups.
  The i-th of the next M lines begins with a positive integer Bi representing the number of teams in the i-th group, followed by Bi nonnegative integers representing the score of each team in this group.


number of test cases <= 10
M<= 100
B[i]<= 20000
score of each team <= 20000

 

 

Output

For each test case, output M lines. Output ``F" (without quotes) if the scores in the i-th group must be false, output ``T" (without quotes) otherwise. See samples for detail.

 

 

Sample Input

2

3

0 5 1

2

1 1

 

 

Sample Output

F

T

 

 

#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <iostream>

#define INF 0x3f3f3f3f

using namespace std;

int main()
{
    int cas,n;
    while(cin >> cas)
    {
        while(cas--)
        {
            scanf("%d",&n);
            int dd;
            int n1 = 0,n2 = 0;
            for(int i=0;i<n;i++)
            {
                scanf("%d",&dd);
                n1 += dd;
                n2 = max(dd,n2);
            }
            if(n2<=2*(n-1)&&n2>=n-1&&n1==(n-1)*n)
                printf("T\n");
            else
                printf("F\n");
        }
    }
}