UVa11968 - In The Airport

本文深入探讨了AI音视频处理领域中的视频分割与语义识别技术,介绍了其在自动驾驶、AR增强现实等场景的应用,以及在实现过程中所涉及的关键算法与实践案例。

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R  — In The Airport

Time Limit: 1 sec
Memory Limit: 32 MB

It’s a Wednesday night and Bob is sitting at the airport and waiting for an airplain to Lithuania. The challenge he is facing is to come up with an easy task for the qualification contest on Saturday in KTU. Unfortunately, he doesn’t have any more ideas because it’s already late and he is too exhausted.

To freshen up, he thinks that he should get a drink and a piece of cake. Waitress gives Bob a menu to choose from. As he was too busy thinking about how tired he is, he simply decided to go for a drink and piece of cake which are the closest to the average of all items on the menu. If he needs to choose, he always goes for the cheaper item. Unfortunately waitress is not very good at math, and obviously she needs your help!

INPUT

You are given (T ≤ 100) tests on the first line. Each test starts with a line containing the integers NM,K, where (2 ≤ N ≤ 1000) is the number of items on the menu, (1 ≤ M ≤ N) is the number of cakes on the menu and (1 ≤ K ≤ N) is the number of drinks on the menu. Next line contains exactly N positive integers, where the first M integers specify the prices for cakes, next K integers (0 ≤ Pi ≤ 109) specify drink prices, and the following prices are for all other items on the menu.

OUTPUT

For each test case you have to output a line "Case #T: A B". Where T is the test case number, A specifies the closest price of the cake to the average of all items, and B is the closest price of the drink to the average of all items. Refer sample output for details.

SAMPLE INPUT

2
4 1 1
1 2 3 4
5 1 2
500000000 5 6 1000000000 1000000000

SAMPLE OUTPUT

Case #1: 1 2
Case #2: 500000000 6

import java.io.IOException;
import java.io.FileInputStream;
import java.io.InputStreamReader;
import java.io.BufferedReader;
import java.io.PrintWriter;
import java.io.OutputStreamWriter;
import java.io.StreamTokenizer;

public class Main
{
	public static boolean DEBUG = false;
	public BufferedReader cin;
	public PrintWriter cout;
	public StreamTokenizer tokenizer;
	public int n, m, k;
	public long total;
	public long[] mArr, nArr, kArr;
	
	public void init()
	{
		try {
			if (DEBUG) {
				cin = new BufferedReader(new InputStreamReader(
						new FileInputStream("d:\\OJ\\uva_in.txt")));
			} else {
				cin = new BufferedReader(new InputStreamReader(System.in));
			}
		} catch (IOException e) {
			e.printStackTrace();
		}
		
		cout = new PrintWriter(new OutputStreamWriter(System.out));
		tokenizer = new StreamTokenizer(cin);
	}
	
	public String next()
	{
		try {
			tokenizer.nextToken();
			if (tokenizer.ttype == StreamTokenizer.TT_EOF)
				return null;
			else if (tokenizer.ttype == StreamTokenizer.TT_WORD)
				return tokenizer.sval;
			else if (tokenizer.ttype == StreamTokenizer.TT_NUMBER) 
				return String.valueOf((int)tokenizer.nval);
		} catch (IOException e) {
			e.printStackTrace();
		}
		
		return null;
		
	}
	
	public void input()
	{
		try {
			n = Integer.parseInt(next());
			m = Integer.parseInt(next());
			k = Integer.parseInt(next());
			
			total = 0;
			mArr = new long[m];
			kArr = new long[k];
			nArr = new long[n - m - k];
			
			for (int i = 0; i < m; i++) {
				mArr[i] = Long.parseLong(next());
				total += mArr[i];
			}
			
			for (int i = 0; i < k; i++) {
				kArr[i] = Long.parseLong(next());
				total += kArr[i];
			}
			
			int tmpn = n - m - k;
			for (int i = 0; i < tmpn; i++) {
				nArr[i] = Long.parseLong(next());
				total += nArr[i];
			}
			
		} catch (Exception e) {
			e.printStackTrace();
		}
	}
	
	
	public void solve(int t)
	{
		cout.printf("Case #%d: ", t);
		
		int ans1 = 0, ans2 = 0;
		
		for (int i = 0; i < m; i++) {
			long tmp1 = n * mArr[i] - total;
			long tmp2 = n * mArr[ans1] - total;
			
			if (Math.abs(tmp1) < Math.abs(tmp2)) ans1 = i;
			else if (Math.abs(tmp1) == Math.abs(tmp2) && mArr[i] < mArr[ans1]) ans1 = i;
		}
		
		for (int i = 0; i < k; i++) {
			long tmp1 = n * kArr[i] - total;
			long tmp2 = n * kArr[ans2] - total;
			
			if (Math.abs(tmp1) < Math.abs(tmp2)) ans2 = i;
			else if (Math.abs(tmp1) == Math.abs(tmp2) && kArr[i] < kArr[ans2]) ans2 = i;
		}
		
		cout.printf("%d %d", mArr[ans1], kArr[ans2]);
		cout.println();
		cout.flush();
	}
	
	public static void main(String[] args)
	{
		try {
			Main solver = new Main();
			solver.init();
			
			int t = Integer.parseInt(solver.next());
			for (int i = 1; i <= t; i++) {
				solver.input();
				solver.solve(i);
			}
		} catch (Exception e) {
			e.printStackTrace();
		}
	}
}



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