wind14的博客

#include #include using namespace std;int main(){    for(int n=0;n    cout    cout    cout    cout>>>>>>>>>>>"    }    return 0;}这种写法只能将十进制数转换为十进制的、八进制、十六进制的。

Text ReverseTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 29094 Accepted Submission(s): 11433Problem DescriptionIgnatius likes to write wo

How Many Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 27055 Accepted Submission(s): 13465Problem DescriptionToday is Ignatius’ b

The TriangleTime Limit: 1000MS Memory Limit: 10000K Total Submissions: 46949 Accepted: 28429 Description7 3 8 8 1 0 2 7 4 4 4 5 2 6 5(Figure 1) Figure 1 shows a n

Description给出两个字符串，求出两个字符串的公共子串？sample Inputencodingmy mydecodingsample Outputcoding两种方法：//暴力求解最长公共子串 public static void enumString(char[]s1 ,char[]s2){ int run_Count = 0;//运行次数 in

Charm Bracelet Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 36441 Accepted: 15968 DescriptionBessie has gone to the mall’s jewelry store and spies a charm bracelet. Of cour

A hard puzzle Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 42082 Accepted Submission(s): 15159Problem Description lcy gives a hard puzz

简单数论题，求最小公倍数。 最小公倍数 = a * b/gcd(a,b);//gcd（a,b）:最大公约数import java.util.Scanner;public class Main { //最大公约数 public static int gcd(int a,int b){ if(b == 0) return a; return gcd(b,

Eddy’s mistakesTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11202 Accepted Submission(s): 6312Problem Description Eddy usually writes ar

Lowest BitTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11797 Accepted Submission(s): 8581Problem DescriptionGiven an positive integer A (

18岁生日Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 31343 Accepted Submission(s): 10153Problem DescriptionGardon的18岁生日就要到了，他当然很开心，可是他突然想到一个

吃糖果 Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 37734 Accepted Submission(s): 10852Problem Description HOHO，终于从Speakless手上赢走了所有的糖果，是Ga

{A} + {B} Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 20170 Accepted Submission(s): 8370Problem Description 给你两个集合，要求{A} + {B}. 注:同一

The Drunk Jailer Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 1834 Accepted Submission(s): 1445Problem Description A certain prison con

开门人和关门人Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15862 Accepted Submission(s): 8103Problem Description每天第一个到机房的人要把门打开，最后一个离开的人要把门关好。现有

A + BTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 16085 Accepted Submission(s): 9600Problem Description 读入两个小于100的正整数A和B,计算A+B. 需要注意的是

人见人爱A-BTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 55406    Accepted Submission(s): 15613Problem Description参加过上个月月赛的同学一定还记得

饭卡Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 16410    Accepted Submission(s): 5704Problem Description电子科大本部食堂的饭卡有一种很诡异的设计，即在购买之

Climbing WormTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 14400    Accepted Submission(s): 9719Problem DescriptionAn inch worm is

A + B AgainTime Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 19955    Accepted Submission(s): 8583Problem DescriptionThere must be man

复习时间Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6438    Accepted Submission(s): 4739Problem Description为了能过个好年，xhd开始复习了，于是每天晚上背着

不要62Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 29113    Accepted Submission(s): 10215Problem Description杭州人称那些傻乎乎粘嗒嗒的人为62（音：lao

基础题：1000、1001、1004、1005、1008、1012、1013、1014、1017、1019、1021、1028、1029、1032、1037、1040、1048、1056、1058、1061、1070、1076、1089、1090、1091、1092、1093、1094、1095、1096、1097、1098、1106、1108、1157、1163、1164、1170、

2015/5/9 背包问题——“01背包”详解及实现（包含背包中具体物品的求解） - wumuzi520的专栏 - 博客频道 - youkuaiyun.comdata:text/html;charset=utf-8,%3Cp%20align%3D%22right%22%20style%3D%22margin%3A%200px%3B%20padding%3A%200px%3B%20color%… 1/6

畅通工程Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 38037    Accepted Submission(s): 20145Problem Description某省调查城镇交通状况，得到现有城镇道路统计表，

import java.util.Scanner;import java.math.*;public class biginteger{public static void main(String[] args){Scanner cin=new Scanner(System.in);BigInteger a,b;while(cin.hasNext()){a=cin.

u Calculate eTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 35737    Accepted Submission(s): 16113Problem DescriptionA simple mathe

I NEED A OFFER!Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 26247 Accepted Submission(s): 10639Problem DescriptionSpeakless很早就想出国，现在他已经考完

简单计算器Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 19484 Accepted Submission(s): 6860Problem Description读入一个只包含 +, -, *, / 的非负整数计算表达式，计算该表

题目内容： 每个非素数（合数）都可以写成几个素数（也可称为质数）相乘的形式，这几个素数就都叫做这个合数的质因数。比如，6可以被分解为2x3，而24可以被分解为2x2x2x3。 现在，你的程序要读入一个[2,100000]范围内的整数，然后输出它的质因数分解式；当读到的就是素数时，输出它本身。 输入格式: 一个整数，范围在[2,100000]内。 输出格式：