#训练5# 1-奥运排行榜

题目

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思路

结构体的排序,要注意名次相等
在这里插入图片描述

代码

#include <iostream>
#include <iostream>
#include <cstring>
#include <stack>
#include <algorithm>
#include <queue>
#include <map>
#include <string>

#define MAXX 250
using namespace std;
int n, m;
struct node
{
    int num;
    int gold;
    int medal;
    int people;
    double pgold;
    double pmedal;
} country[MAXX];
int t[MAXX];
int p1[MAXX], p2[MAXX], p3[MAXX], p4[MAXX];

bool cmp1(node a, node b)
{
    return a.gold > b.gold;
}

bool cmp2(node a, node b)
{
    return a.medal > b.medal;
}

bool cmp3(node a, node b)
{
    return a.pgold > b.pgold;
}

bool cmp4(node a, node b)
{
    return a.pmedal > b.pmedal;
}

int main()
{
    cin >> n >> m;
    for (int i = 0; i < n; ++i)
    {
        cin >> country[i].gold >> country[i].medal >> country[i].people;
        country[i].num = i;
        country[i].pgold = (double) country[i].gold / country[i].people;
        country[i].pmedal = (double) country[i].medal / country[i].people;
    }
    //111111111
    sort(country, country + n, cmp1);
    int level = 1;
    p1[country[0].num] = level++;  //注意这里等级就要改变了
    for (int i = 1; i < n; ++i)
    {
        if (country[i].gold == country[i - 1].gold)
            p1[country[i].num] = p1[country[i - 1].num];
        else
            p1[country[i].num] = level;  //这里不改变
        level++;
    }

    //2222222222
    sort(country, country + n, cmp2);
    level = 1;
    p2[country[0].num] = level++;
    for (int i = 1; i < n; ++i)
    {
        if (country[i].medal == country[i - 1].medal)
            p2[country[i].num] = p2[country[i - 1].num];
        else
            p2[country[i].num] = level;
        level++;
    }

    //33333333
    sort(country, country + n, cmp3);
    level = 1;
    p3[country[0].num] = level++;
    for (int i = 1; i < n; ++i)
    {
        if (country[i].pgold == country[i - 1].pgold)
            p3[country[i].num] = p3[country[i - 1].num];
        else
            p3[country[i].num] = level;
        level++;
    }

    //44444444
    sort(country, country + n, cmp4);
    level = 1;
    p4[country[0].num] = level++;
    for (int i = 1; i < n; ++i)
    {
        if (country[i].pmedal == country[i - 1].pmedal)
            p4[country[i].num] = p4[country[i - 1].num];
        else
            p4[country[i].num] = level;
        level++;
    }

    //aaaaaaaaaa
    for (int i = 0; i < m; ++i)  //最后一个一个来比较
    {
        cin >> t[i];
    }
    for (int i = 0; i < m; ++i)
    {
        int no,minn = MAXX;
        if (p1[t[i]]<minn)
        {
            no=1;
            minn = p1[t[i]];
        }
        if (p2[t[i]]<minn)
        {
            no=2;
            minn = p2[t[i]];
        }
        if (p3[t[i]]<minn)
        {
            no=3;
            minn = p3[t[i]];
        }
        if (p4[t[i]]<minn)
        {
            no=4;
            minn = p4[t[i]];
        }
        if (i!=0)
            cout<<' ';
        cout<<minn<<":"<<no;
    }
    return 0;
}

总结

  1. double类型不能直接接收int,会丢失小数点,要进行类型的强制转化
  2. 思路要考虑的全面,不能只是样例输出的正确,要全部通用
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