PAT_AL_1002 A+B for Polynomials

题目链接
This time, you are supposed to find A+B where A and B are two polynomials.
Input Specification:

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:

K N​1​​ a​N​1​​​​ N​2​​ a​N​2​​​​ … N​K​​ a​N​K​​​​

where K is the number of nonzero terms in the polynomial, N​i​​ and a​N​i​​​​ (i=1,2,⋯,K) are the exponents and coefficients, respectively. It is given that 1≤K≤10,0≤N​K​​<⋯<N​2​​<N​1​​≤1000.
Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

#include <iostream>

using namespace std;

int main()
{
    int n,m;
    float ploy[1005];
    for(int i=0;i<1005;i++)
        ploy[i]=0;
    scanf("%d",&n);
    for(int i=0;i<n;i++)
    {
        int e;
        float c;
        cin>>e>>c;
        ploy[e]+=c;

    }
    scanf("%d",&m);
    for(int i=0;i<m;i++)
    {
        int e;
        float c;
        cin>>e>>c;
        ploy[e]+=c;

    }
    int num=0;
    for(int i=0;i<1005;i++)
        if(ploy[i]!=0)
        num++;
    printf("%d",num);
    for(int i=1004;i>=0;i--)
        if(ploy[i]!=0)
        printf(" %d %.1f",i,ploy[i]);
    return 0;
}

  • polynomials: 多项式
  • exponents: 指数,幂
  • coefficients: 系数
1002 A+B for Polynomials 是一道编程题目,通常是在考察Java中处理多项式加法的问题。在这个问题中,你需要编写一个程序,让用户输入两个多项式的系数(如a_n*x^n + a_{n-1}*x^{n-1} + ... + a_1*x + a_0的形式),然后计算它们的和,并按照同样的形式表示出来。 在Java中,你可以创建一个`Polynomial`类,包含一个数组来存储系数和最高次数的信息。用户输入的每个多项式可以被解析成这样的结构,然后通过遍历并累加系数来完成加法操作。最后,将结果转换回字符串形式展示给用户。 以下是简化版的代码示例: ```java class Polynomial { int[] coefficients; int degree; // 构造函数,初始化数组 public Polynomial(int[] coeffs) { coefficients = coeffs; degree = coefficients.length - 1; } // 加法方法 Polynomial add(Polynomial other) { Polynomial result = new Polynomial(new int[coefficients.length + other.coefficients.length]); for (int i = 0; i < coefficients.length; ++i) { result.coefficients[i] += coefficients[i]; } for (int i = 0; i < other.coefficients.length; ++i) { result.coefficients[i + coefficients.length] += other.coefficients[i]; } result.degree = Math.max(degree, other.degree); return result; } @Override public String toString() { StringBuilder sb = new StringBuilder(); if (degree >= 0) { for (int i = degree; i >= 0; --i) { sb.append(coefficients[i]).append('*x^').append(i).append(" + "); } // 移除最后一个 " + " sb.setLength(sb.length() - 2); } else { sb.append("0"); } return sb.toString(); } } // 主函数示例 public static void main(String[] args) { Polynomial poly1 = new Polynomial(...); // 用户输入第一个多项式的系数 Polynomial poly2 = new Polynomial(...); // 用户输入第二个多项式的系数 Polynomial sum = poly1.add(poly2); System.out.println("Result: " + sum); } ```
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