Educational Codeforces Round 67 (Rated for Div. 2) B. Letters Shop

本文介绍了一个关于字符串匹配的问题,其中涉及到如何从一个展示串中找出最短前缀,以覆盖一组朋友名字的所有字符,每个名字的构造需确保字符数量足够。通过算法解决这一问题,我们能够有效地确定每个朋友需要购买的最小字母数量。

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B. Letters Shop

The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.

Letters are sold one by one from the leftmost to the rightmost. Any customer can only buy some prefix of letters from the string s.

There are m friends, the i-th of them is named ti. Each of them is planning to estimate the following value: how many letters (the length of the shortest prefix) would s/he need to buy if s/he wanted to construct her/his name of bought letters. The name can be constructed if each letter is presented in the equal or greater amount.

For example, for s=“arrayhead” and ti=“arya” 5 letters have to be bought (“arrayhead”).
For example, for s=“arrayhead” and ti=“harry” 6 letters have to be bought (“arrayhead”).
For example, for s=“arrayhead” and ti=“ray” 5 letters have to be bought (“arrayhead”).
For example, for s=“arrayhead” and ti=“r” 2 letters have to be bought (“arrayhead”).
For example, for s=“arrayhead” and ti=“areahydra” all 9 letters have to be bought (“arrayhead”).
It is guaranteed that every friend can construct her/his name using the letters from the string s.

Note that the values for friends are independent, friends are only estimating them but not actually buying the letters.

Input

The first line contains one integer n (1≤n≤2⋅105) — the length of showcase string s.

The second line contains string s, consisting of exactly n lowercase Latin letters.

The third line contains one integer m (1≤m≤5⋅104) — the number of friends.

The i-th of the next m lines contains ti (1≤|ti|≤2⋅105) — the name of the i-th friend.

It is guaranteed that ∑i=1m|ti|≤2⋅105.

Output

For each friend print the length of the shortest prefix of letters from s s/he would need to buy to be able to construct her/his name of them. The name can be constructed if each letter is presented in the equal or greater amount.

It is guaranteed that every friend can construct her/his name using the letters from the string s.

Example

input

9
arrayhead
5
arya
harry
ray
r
areahydra

output

5
6
5
2
9

代码:

#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstring>
#include <string>
#include <cmath>
#include <stack>
#include <queue>
#include <vector>
#include <set>
#include <map>
#include <functional>
#include <ctime>
#include <iomanip>
#include <sstream>
#include <algorithm>
#define ll long long
#define ull unsigned long long
#define dd double
#define mes(x,y) memset(x,y,sizeof(x))
using namespace std;
 
const int maxn=2e4+9;
const int mod=1e8+7;
 
ll GCD(ll a,ll b) {//最大公约数
    return b == 0 ? a : GCD(b, a % b);
}
 
int main() {
    std::ios::sync_with_stdio(false);
    ll x,y,z,n,m,i,j;
    string s1,s2;
    while (cin >> n>>s1>>m) {
        ll len=s1.length();
        map<pair<char,ll>,ll>mm;mm.clear();
        pair<char,ll>st;
        map<char,ll>vc;vc.clear();
        for(i=0;i<len;i++){
            vc[s1[i]]++;
            st.first=s1[i];
            st.second=vc[s1[i]];
            mm[st]=i;
        }
        while(m--){
            cin>>s2;ll len2=s2.length(),maxn=-1;
            vc.clear();
            for(i=0;i<len2;i++){
                vc[s2[i]]++;
                st.first=s2[i];
                st.second=vc[s2[i]];
                maxn=max(maxn,mm[st]);
                if(maxn==len-1)break;
            }
            maxn++;
            cout<<maxn<<endl;
        }
    }
}
"educational codeforces round 103 (rated for div. 2)"是一个Codeforces平台上的教育性比赛,专为2级选手设计评级。以下是有关该比赛的回答。 "educational codeforces round 103 (rated for div. 2)"是一场Codeforces平台上的教育性比赛。Codeforces是一个为程序员提供竞赛和评级的在线平台。这场比赛是专为2级选手设计的,这意味着它适合那些在算法和数据结构方面已经积累了一定经验的选手参与。 与其他Codeforces比赛一样,这场比赛将由多个问题组成,选手需要根据给定的问题描述和测试用例,编写程序来解决这些问题。比赛的时限通常有两到三个小时,选手需要在规定的时间内提交他们的解答。他们的程序将在Codeforces的在线评测系统上运行,并根据程序的正确性和效率进行评分。 该比赛被称为"educational",意味着比赛的目的是教育性的,而不是针对专业的竞争性。这种教育性比赛为选手提供了一个学习和提高他们编程技能的机会。即使选手没有在比赛中获得很高的排名,他们也可以从其他选手的解决方案中学习,并通过参与讨论获得更多的知识。 参加"educational codeforces round 103 (rated for div. 2)"对于2级选手来说是很有意义的。他们可以通过解决难度适中的问题来测试和巩固他们的算法和编程技巧。另外,这种比赛对于提高解决问题能力,锻炼思维和提高团队合作能力也是非常有帮助的。 总的来说,"educational codeforces round 103 (rated for div. 2)"是一场为2级选手设计的教育性比赛,旨在提高他们的编程技能和算法能力。参与这样的比赛可以为选手提供学习和进步的机会,同时也促进了编程社区的交流与合作。
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