A. Translation

最新推荐文章于 2019-05-05 16:45:10 发布

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最新推荐文章于 2019-05-05 16:45:10 发布

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分类专栏： C++解决的算法题

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本文介绍了一个编程挑战，要求判断一个单词从Berlandish语言翻译成Birlandish语言（即反转字符串）是否正确。通过C语言程序实现，比较输入的两个单词，若第二个单词为第一个单词的反转，则输出YES，否则输出NO。

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A. Translation

time limit per test2 seconds
memory limit per test256 megabytes
inputstandard input
outputstandard output
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it’s easy to make a mistake during the «translation». Vasya translated word s from Berlandish into Birlandish as t. Help him: find out if he translated the word correctly.

Input
The first line contains word s, the second line contains word t. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.

Output
If the word t is a word s, written reversely, print YES, otherwise print NO.

问题链接：A. Translation.

问题简述：

第一行：一行英文字符
第二行：A同学转换后的英文字符
问：他转换的对不对，对：输出“YES”；不对：输出“NO”。
（转换规则，倒过来写一遍）

程序说明：

AC通过的C语言程序如下：

#include<iostream>
#include<string>
using namespace std;

int main()
{
	string s,t;
	getline(cin,s);//保存第一行字符
	getline(cin,t);//保存第二行字符
	int is,it;//保存两行字符的大小
	is = s.size();
	it = t.size();
	if(is!=it)//如果大小不对，肯定错了
	{
		cout<<"NO";
		return 0;	
	}
	for(int i=0;i<is;i++)
	{
		if(s[i]!=t[it-i-1])//比较是否一致
		{
			cout<<"NO";
			return 0;
		}
	}
	cout<<"YES";
	return 0;
}