Problem 62 : Cubic permutations
The cube, 41063625 (3453), can be permuted to produce two other cubes: 56623104 (3843) and 66430125 (4053). In fact, 41063625 is the smallest cube which has exactly three permutations of its digits which are also cube.
Find the smallest cube for which exactly five permutations of its digits are cube.
C++ 代码 (如果打开编译开关 CPP_11,则要C+11编译器支持)
#include <iostream>
#include <string>
#include <vector>
#include <iterator>
#include <cmath>
#include <map>
#include <algorithm>
#include <cassert>
#include <ctime>
using namespace std;
#define CPP_11
//#define UNIT_TEST
typedef struct CubicPermutation
{
int number;
long long cube; // number*number*number = cube
string digits;
} CubicPermutation;
class PE0062
{
private:
string getDigitsString(long long number);
bool checkCubicPermutations(map<string, int>& cubicPermu_mp,
vector<CubicPermutation>& cubicPermu,
long long& smallest_cube,
const int max_permutations);
public:
long long findSmallestCube(const int max_permutations,
int range_start, int range_end);
};
string PE0062::getDigitsString(long long number)
{
#ifndef CPP_11
vector<int> digit_vec;
while (number > 0)
{
digit_vec.push_back(number % 10); // 197 => digits: 7, 9, 1
number /= 10;
}
sort(digit_vec.begin(), digit_vec.end());
vector<int>::iterator iter;
string digits_str(digit_vec.begin(), digit_vec.end());
for (unsigned int i = 0; i < digit_vec.size(); i++)
{
digits_str[i] = (char)(digit_vec[i] + '0');
}
#else
string digits_str = to_string(number); // C++ 11
sort(digits_str.begin(), digits_str.end());
#endif
return digits_str;
}
bool PE0062::checkCubicPermutations(map<string, int>& cubicPermu_mp,
vector<CubicPermutation>& cubicPermu,
long long& smallest_cube,
const int max_permutations)
{
map<string, int>::iterator iter;
for (iter = cubicPermu_mp.begin(); iter != cubicPermu_mp.end(); iter++)
{
if (max_permutations == iter->second)
{
vector<CubicPermutation>::iterator iter1;
int number_of_Permutations = 0;
for (iter1 = cubicPermu.begin(); iter1 != cubicPermu.end(); iter1++)
{
if (iter1->digits == iter->first)
{
if (0 == smallest_cube)
{
smallest_cube = iter1->cube;
}
#ifdef UNIT_TEST
cout << iter1->cube << " (" << iter1->number << "^3)"<<endl;
#endif
number_of_Permutations++;
if (max_permutations == number_of_Permutations)
{
break;
}
}
}
return true;
}
}
return false;
}
long long PE0062::findSmallestCube(const int max_permutations,
int range_start, int range_end)
{
vector<CubicPermutation>cubicPermu;
map<string, int>cubicPermu_mp;
CubicPermutation cp;
for (long long number = range_start; number < range_end; number++)
{
cp.number = (int)number;
cp.cube = number * number*number;
cp.digits = getDigitsString(cp.cube);
cubicPermu.push_back(cp);
cubicPermu_mp[cp.digits]++;
}
long long smallest_cube = 0;
if (true == checkCubicPermutations(cubicPermu_mp, cubicPermu,
smallest_cube, max_permutations))
{
return smallest_cube;
}
return 0;
}
int main()
{
#ifdef UNIT_TEST
clock_t start = clock();
#endif
PE0062 pe0062;
assert(41063625 == pe0062.findSmallestCube(3, 100, 1000));
const int max_permutations = 5;
long long smallest_cube = pe0062.findSmallestCube(max_permutations,
406, 10000);
cout << "The smallest cube for which exactly " << max_permutations;
cout << " permutations of its digits are cube is ";
cout << smallest_cube << "." << endl;
#ifdef UNIT_TEST
clock_t finish = clock();
double duration = (double)(finish - start) / CLOCKS_PER_SEC;
cout << "C/C++ running time: " << duration << " seconds" << endl;
#endif
return 0;
}
Python 代码
def checkCubicPermutations(cubicPermu_dict, cubicPermu_list, max_permutations):
smallest_cube = 0
for key, value in cubicPermu_dict.items():
if value == max_permutations:
number_of_Permutations = 0
for cp in cubicPermu_list:
if cp[2] == key:
if 0 == smallest_cube:
smallest_cube = cp[1]
print(cp[1], " (%d^3)" % cp[0])
number_of_Permutations += 1
if max_permutations == number_of_Permutations:
break
return smallest_cube
return 0
def findSmallestCube(max_permutations, range_start, range_end):
cubicPermu_list = []
cubicPermu_dict = {}
for number in range(range_start, range_end):
cube = number*number*number
# cube_str = str(cube)
# str_list = list(cube_str)
# str_list.sort()
# digits_str = ''.join(str_list)
digits_str = ''.join((lambda x:(x.sort(),x)[1])(list(str(cube))))
cubicPermu_list += [[ number, cube, digits_str ]]
if digits_str in cubicPermu_dict.keys():
cubicPermu_dict[digits_str] += 1
else:
cubicPermu_dict[digits_str] = 1
smallest_cube = checkCubicPermutations(cubicPermu_dict,\
cubicPermu_list, max_permutations)
return smallest_cube
def main():
assert 41063625 == findSmallestCube(3, 100, 1000)
max_permutations = 5
smallest_cube = findSmallestCube(max_permutations, 406, 10000)
print("The smallest cube for which exactly %d" % max_permutations,end='')
print(" permutations of its digits are cube is %d." % smallest_cube)
if __name__ == '__main__':
main()