boost lexical_cast

最新推荐文章于 2025-09-12 18:45:12 发布

转载最新推荐文章于 2025-09-12 18:45:12 发布 · 80 阅读

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原文链接：http://www.cnblogs.com/sssblog/p/10978528.html

文章标签：

#c/c++

本文介绍了Boost.LexicalCast库的使用方法，演示了如何使用boost::lexical_cast操作符在字符串与数值类型如int、double之间进行转换。通过代码示例展示了基本用法，并提到了内部使用流进行转换的原理及失败时会抛出boost::bad_lexical_cast异常。

Boost.LexicalCast provides a cast operator, boost::lexical_cast, that can covert numberes from strings to numeric types like int or double.

#include <boost/lexical_cast.hpp>
#include <string>
#include <iostream>

int main() {
  std::string s = boost::lexical_cast<std::string>(123);
  std::cout << s << std::endl;
  double d = boost::lexical_cast<double>(s);
  std::cout << d << std::endl;
  return 0;
}

boost::lexical_cast uses streams internally to perform the conversion. Therefore, only types with overloader operator<< and operator>> can be converted.

If a conversion fails, an exception of type boost::bad_lexical_cast, which is derived from std::bad_cast, is thrown.

转载于:https://www.cnblogs.com/sssblog/p/10978528.html