一、枚举所有宽度为举着宽度的子矩阵,从中找出是否具有相应长度的正方形,复杂度为O(n^3);
二、[1]中使用动态规划,decrease the complexity to O(n^2)
dp[i][j] mean the maximum square which has right-down corner (i,j)
the transform function is listed as below:
dp[i][j] = min(dp[i-1][j],dp[i][j-1],dp[i-1][j])+1;
转载于:https://www.cnblogs.com/deepblueme/p/4694064.html