题目:Given an array of non-negative integers, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that position.
Your goal is to reach the last index in the minimum number of jumps.
For example: Given array A = [2,3,1,1,4]
The minimum number of jumps to reach the last index is 2. (Jump 1 step from index 0 to 1, then 3 steps
to the last index.)
解题代码如下:
// 时间复杂度 O(n),空间复杂度 O(1)
class Solution {
public:
int jump(vector<int>& nums) {
int step = 0; // 最小步数
int left = 0;
int right = 0; // [left, right] 是当前能覆盖的区间
if (nums.size() == 1) return 0;
while (left <= right) { // 尝试从每一层跳最远
++step;
int old_right = right;
for (int i = left; i <= old_right; ++i) {
int new_right = i + nums[i];
if (new_right >= nums.size() - 1)
return step;
if (new_right > right) right = new_right;
}
left = old_right + 1;
}
return 0;
}
};
上面代码的思想及编写参考了网址https://github.com/soulmachine/leetcode#leetcode题解题目