ARM C嵌套汇编&NEON运算小例子

最新推荐文章于 2024-06-12 21:23:37 发布

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#ARM #汇编 #NEON

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本文展示了一个使用ARM Neon指令集和内联汇编(ASM)进行数组操作的C语言示例程序。该程序初始化了一个整数数组，并通过内联汇编加载数据到Neon寄存器中进行处理，然后将结果存储回数组。此例适用于嵌入式系统和移动设备上的高性能计算。

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#include <stdio.h>
#include <stdlib.h>
#include <arm_neon.h>

int main()
{

	int x[10]={0};
	int *x_value;
	x_value=x;
	int data;

	asm(
		
		"	str	 fp, [sp, #-4]! \n\t"
		"	add	fp, sp, #0   \n\t"
                /*1-8*/
		"	mov 	r3, #1   \n\t"
		"	strb r3, [fp, #-48]      \n\t"

		"	mov r3,#2 \n\t"
		"	strb r3, [fp, #-47]      \n\t"

		"	mov 	r3, #3   \n\t"
		"	strb r3, [fp, #-46]      \n\t"

		"	mov r3,#4 \n\t"
		"	strb r3,[fp,#-45]  \n\t"

		"	mov 	r3, #5   \n\t"
		"	strb r3, [fp, #-44]      \n\t"

		"	mov r3,#6 \n\t"
		"	strb r3,[fp,#-43]  \n\t"

		"	mov r3,#7 \n\t"
		"	strb r3,[fp,#-42]  \n\t"

		"	mov r3,#8 \n\t"
		"	strb r3,[fp,#-41]  \n\t"
		/*9-16*/
		"	mov 	r3, #9   \n\t"
		"	strb r3, [fp, #-40]      \n\t"

		"	mov r3,#10 \n\t"
		"	strb r3, [fp, #-39]      \n\t"

		"	mov 	r3, #11   \n\t"
		"	strb r3, [fp, #-38]      \n\t"

		"	mov r3,#12 \n\t"
		"	strb r3,[fp,#-37]  \n\t"

		"	mov 	r3, #13   \n\t"
		"	strb r3, [fp, #-36]      \n\t"

		"	mov r3,#14 \n\t"
		"	strb r3,[fp,#-35]  \n\t"

		"	mov r3,#14 \n\t"
		"	strb r3,[fp,#-34]  \n\t"

		"	mov r3,#16 \n\t"
		"	strb r3,[fp,#-33]  \n\t"

		

		
		"    sub r3, fp,#48 \n\t"//back to [fp,#-48]
		"	vld1.8 {d16},[r3]  \n\t"//load to neon register,

		"    sub r3,fp, #40 \n\t"//back to [fp,#32]
		"	vld1.8 {d17},[r3]  \n\t" //load to neon register,
		"	vadd.i8 d0,d16,d17  \n\t"     

		"    sub r3, fp,#200 \n\t"
		"	vst1.8 {d0}, [r3]  \n\t"


		

		"    ldrb r3,[fp,#-200]   \n\t"
		"    str r3,[%[x],#0]  \n\t"

		"    ldrb r3,[fp,#-199]   \n\t"
		"    str r3,[%[x],#4]  \n\t"

		"    ldrb r3,[fp,#-198]  \n\t"
		"    str r3,[%[x],#8]  \n\t"

		"    ldrb r3,[fp,#-197]   \n\t"
		"    str r3,[%[x],#12]  \n\t"

		"    ldrb r3,[fp,#-196]   \n\t"
		"    str r3,[%[x],#16]  \n\t"

		"    ldrb r3,[fp,#-195]   \n\t"
		"    str r3,[%[x],#20]  \n\t"

		"    ldrb r3,[fp,#-194]  \n\t"
		"    str r3,[%[x],#24]  \n\t"

		"    ldrb r3,[fp,#-193]   \n\t"
		"    str r3,[%[x],#28]  \n\t"

	
		"	mov %[data],r3 \n\t"
		"	ldr	fp, [sp], #4   \n\t"

		:[x]"+r"(x_value),[data]"+r"(data)
		:
		:"r0","r3","memory"

		);

	int i;
	for(i=0;i<10;i++)
		printf("%d:%d-%d\n",i,x[i],data);
	return 0;

}

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