Distinct powers
Problem 29
Consider all integer combinations of ab for 2 ≤ a ≤ 5 and 2 ≤ b ≤ 5:
22=4, 23=8, 24=16, 25=32
32=9, 33=27, 34=81, 35=243
42=16, 43=64, 44=256, 45=1024
52=25, 53=125, 54=625, 55=3125
If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms:
4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125
How many distinct terms are in the sequence generated by ab for 2 ≤ a ≤ 100 and 2 ≤ b ≤ 100?
这套题也在网上看了其他大神的解决方案,但是我觉得是不是复杂了一些,其实可以很简单的完成,比如这样:
numlist = []
#创建分组 for i in range(2,101,1):
#给出a的范围 for j in range(2,101,1):
#给出b的范围 s = i ** j
#求出a的b次方的数值 if s in numlist: continue
else:
numlist.append(s)
#将数值插入分组,如果还没有出现过的话
print(len(numlist))答案为:9183