project Eulert 学习笔记之 problem 22

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解析一个包含五千个英文名字的文件，按字母顺序排列并计算每个名字的得分，最终求得所有名字的总分。

Using names.txt (right click and 'Save Link/Target As...'), a 46K text file containing over five-thousand first names, begin by sorting it into alphabetical order. Then working out the alphabetical value for each name, multiply this value by its alphabetical position in the list to obtain a name score.

For example, when the list is sorted into alphabetical order, COLIN, which is worth 3 + 15 + 12 + 9 + 14 = 53, is the 938th name in the list. So, COLIN would obtain a score of 938 × 53 = 49714.

What is the total of all the name scores in the file?

题目解释：给了一个包含5000个英文名字的TXT文本，从A-Z分别定义为1-26，每个名字的得分就是字母分数的总和乘以位数，最终要求得出这5000个名字的总分。

解决方案：

import fileinput,string
f=open("22.txt","r")
s=f.readline()
list=s.split(',')
list.sort()
xx = 0
y = 0
for i in range(0,5163):
sum = 0
xx = 0
for j in range(0,len(list[i])):
if list[i][j] >= 'A' and list[i][j] <= 'Z':
sum += ord(list[i][j]) - ord('A') + 1
xx = sum * (i+1)
y = y + xx
print(y)