#include<cstdio>
#include<iostream>
using namespace std;
int n,d;
double l[100],p[100],v[100];
int main()
{
int k=0;
while(scanf("%d%d",&n,&d)==2&&(n||d))
{
double temp1=0,temp2=0;
k++;
for(int i=0;i<n;i++)
{
scanf("%lf%lf%lf",&p[i],&l[i],&v[i]);
temp1+=2*l[i]/v[i];
temp2+=l[i];
}
printf("Case %d: %.3lf\n\n",k,temp1+d-temp2);
}
return 0;
}
UVA 12230(p333)----Crossing Rivers
最新推荐文章于 2019-06-06 17:49:00 发布