boost python object creation process

本文展示了如何使用Boost.Python将C++类封装到Python中,包括类的构造、属性设置和获取方法。

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Test codes and pipeline

foo.cpp:

#include <boost/python.hpp>
#include <iostream>

namespace bp = boost::python;
using namespace std;

class Foo
{
public:
    Foo(int n) { 
        cout << "in Foo::Foo()" << endl;
        value = n; 
    }
    void set(int n) { value = n; }
    int get() { return value; }
private:
    int value;
};

BOOST_PYTHON_MODULE(foo){
    bp::class_<Foo>("Foo", bp::init<int>())
        .def("get", &Foo::get)
        .def("set", &Foo::set);
}

Makefile:

CPPFLAGS = -I/usr/include/python2.7
CXXFLAGS = -Wall
LDFLAGS = -fPIC -shared
LDLIBS = -lboost_python  -lpython2.7

foo.so: foo.cpp
    $(CXX) $(CPPFLAGS) $(CXXFLAGS) $(LDFLAGS) $^ $(LDLIBS) -o $@

.PHONY: clean
clean:
    rm -f foo.so *.o

test in python:

>>> from foo import Foo
>>> BP = Foo.__base__ # Boost.Python.instance
>>> @staticmethod
>def _Foo_new(cls, *args, **kwargs):
>    print cls
>    print 'args:', args
>    print 'kwargs:', kwargs
>    return BP.__new__(cls, *args, **kwargs)
>>> Foo.__new__ = _Foo_new
>>> f = Foo(23)
<class 'foo.Foo'>
args: (23,)
kwargs: {}
in Foo::Foo()
>>> # "f = F(23)" is equivalent to 
>>> f = Foo.__new__(Foo)
>>> f.__init__(23)
>>> f.get()
23

Inheritance tree

Created with Raphaël 2.1.0 Foo Boost.Python.instance object

Conclusion

Boost.Python

  • wrap instance of C++ class in the wrapper
  • calling order in python:
    1. __new__
    2. __init__
    3. create C++ instance
    4. initialize C++ instance

Reference

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