使用C++标准库std::chrono
记录程序段开始执行时间,结束执行时间,相减后转换成某个时间单位。
example:
#include <iostream>
#include <chrono>
long fibonacci(unsigned n)
{
if (n < 2) return n;
return fibonacci(n-1) + fibonacci(n-2);
}
int main()
{
auto start = std::chrono::steady_clock::now();
std::cout << "f(42) = " << fibonacci(42) << '\n';
auto end = std::chrono::steady_clock::now();
std::chrono::duration<double> elapsed_seconds = end-start;
std::cout << "elapsed time: " << elapsed_seconds.count() << "s\n";
}
output:
f(42) = 267914296
elapsed time: 1.88232s
example2:
#include <iostream>
#include <chrono>
void function()
{
long long number = 0;
for( long long i = 0; i != 2000000; ++i )
{
number += 5;
}
}
int main()
{
auto t1 = std::chrono::high_resolution_clock::now();
function();
auto t2 = std::chrono::high_resolution_clock::now();
auto duration = std::chrono::duration_cast<std::chrono::microseconds>( t2 - t1 ).count();
std::cout << duration;
return 0;
}
更新:打印毫秒间隔时间
#include <iostream>
#include <chrono>
#include <ratio>
#include <thread>
void f()
{
std::this_thread::sleep_for(std::chrono::seconds(1));
}
int main()
{
auto t1 = std::chrono::high_resolution_clock::now();
f();
auto t2 = std::chrono::high_resolution_clock::now();
// floating-point duration: no duration_cast needed
std::chrono::duration<double, std::milli> fp_ms = t2 - t1;
// integral duration: requires duration_cast
auto int_ms = std::chrono::duration_cast<std::chrono::milliseconds>(t2 - t1);
// converting integral duration to integral duration of shorter divisible time unit:
// no duration_cast needed
std::chrono::duration<long, std::micro> int_usec = int_ms;
std::cout << "f() took " << fp_ms.count() << " ms, "
<< "or " << int_ms.count() << " whole milliseconds "
<< "(which is " << int_usec.count() << " whole microseconds)" << std::endl;
}
本文展示了如何利用C++的std::chrono库来记录和计算程序执行的时间,包括 fibonacci 函数的计算时间和循环操作的耗时,并以不同时间单位展示结果。示例中还涉及到高精度时钟的选择和时间间隔的转换,以及通过std::this_thread::sleep_for函数模拟耗时操作。
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