light oj 1265 - Island of Survival(概率dp)

在一个仅存老虎和鹿的荒岛上,参与者必须通过概率计算决定最佳生存策略。此问题探讨了不同动物相遇的各种可能性及参与者的存活概率。

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1265 - Island of Survival
Time Limit: 2 second(s)Memory Limit: 32 MB

You are in a reality show, and the show is way too real that they threw into an island. Only two kinds of animals are in the island, the tigers and the deer. Though unfortunate but the truth is that, each day exactly two animals meet each other. So, the outcomes are one of the following

a)      If you and a tiger meet, the tiger will surely kill you.

b)      If a tiger and a deer meet, the tiger will eat the deer.

c)      If two deer meet, nothing happens.

d)      If you meet a deer, you may or may not kill the deer (depends on you).

e)      If two tigers meet, they will fight each other till death. So, both will be killed.

If in some day you are sure that you will not be killed, you leave the island immediately and thus win the reality show. And you can assume that two animals in each day are chosen uniformly at random from the set of living creatures in the island (including you).

Now you want to find the expected probability of you winning the game. Since in outcome (d), you can make your own decision, you want to maximize the probability.

Input

Input starts with an integer T (≤ 200), denoting the number of test cases.

Each case starts with a line containing two integers t (0 ≤ t ≤ 1000) and d (0 ≤ d ≤ 1000) where t denotes the number of tigers and d denotes the number of deer.

Output

For each case, print the case number and the expected probability. Errors less than 10-6 will be ignored.

Sample Input

Output for Sample Input

4

0 0

1 7

2 0

0 10

Case 1: 1

Case 2: 0

Case 3: 0.3333333333

Case 4: 1

 


SPECIAL THANKS: JANE ALAM JAN (DESCRIPTION, SOLUTION, DATASET)

思路:忽略deer的影响,每次乘以都是老虎相遇的概率


#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<queue>
#include<stack>
#include<vector>
#include<set>
#include<map>


#define L(x) (x<<1)
#define R(x) (x<<1|1)
#define MID(x,y) ((x+y)>>1)

#define eps 1e-8
//typedef __int64 ll;

#define fre(i,a,b)  for(i = a; i <b; i++)
#define free(i,b,a) for(i = b; i >= a;i--)
#define mem(t, v)   memset ((t) , v, sizeof(t))
#define ssf(n)      scanf("%s", n)
#define sf(n)       scanf("%d", &n)
#define sff(a,b)    scanf("%d %d", &a, &b)
#define sfff(a,b,c) scanf("%d %d %d", &a, &b, &c)
#define pf          printf
#define bug         pf("Hi\n")

using namespace std;

#define INF 0x3f3f3f3f
#define N 10005
int tiger,deer;

int main()
{
	int i,j,t,ca=0;
	sf(t);
	while(t--)
	{
       scanf("%d%d",&tiger,&deer);
       printf("Case %d: ",++ca);
       double ans=1;
       if(tiger&1)
	   {
	   	 printf("0.00000000\n");
	   	 continue;
	   }
      while(tiger>0)
	  {
         ans*=tiger*(tiger-1)*1.0/(tiger*(tiger+1));
         tiger-=2;
	  }
       printf("%.7lf\n",ans);
	}

  return 0;
}







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