Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given “egg”, “add”, return true.
Given “foo”, “bar”, return false.
Given “paper”, “title”, return true.
Note:
You may assume both s and t have the same length.
题意:字符串S和T的组成字符只能单对单映射,而且两个字符串内互相映射的字符出现位置必须一致
解决思路:用两个大小为256的数组存储字符串内字符对应的映射关系
代码:
public class Solution {
public boolean isIsomorphic(String s, String t) {
int[] sChars = new int[256];
int[] tChars = new int[256];
for(int i = 0;i < s.length();++i){
if(sChars[s.charAt(i)] != tChars[t.charAt(i)]){
return false;
}else{
sChars[s.charAt(i)] = tChars[t.charAt(i)] = t.charAt(i);
}
}
return true;
}
}