Bitwise AND of Numbers Range

Notes:

即找到m和n共同的位

public class Solution {
    public int rangeBitwiseAnd(int m, int n) {
          int i = 0;
          while(m != n){
        	  m >>= 1;
          	  n >>= 1;
        	  i++;
          }
          return m << i;
      }
}