292. Nim Game

本文介绍了一种Nim游戏的胜负判断策略。通过分析不同数量的石子在双方轮流取走1到3个的情况下,谁将赢得游戏。文章发现了一个规律,即当石子总数为4的倍数时,先手玩家将输掉比赛,反之则赢。

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You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove the stones.

Both of you are very clever and have optimal strategies for the game. Write a function to determine whether you can win the game given the number of stones in the heap.

For example, if there are 4 stones in the heap, then you will never win the game: no matter 1, 2, or 3 stones you remove, the last stone will always be removed by your friend.

思路:找规律

石子数拿法结果
1直接拿1个
2直接拿2个
3直接拿3个
4怎么拿都输
5拿1个给对方留4个
6拿2个给对方留4个

规律就是,如果石子个数是4的倍数,则输,否则赢。
Python 代码:

class Solution(object):
    def canWinNim(self, n):
        """
        :type n: int
        :rtype: bool
        """
        return n % 4 != 0
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