// you can also use includes, for example:
// #include <algorithm>
long long getInversionCount(vector<int>& workArr, int start, int end)
{
if(start >= end) return 0;
int mid = start+(end-start)/2;
long long inversionCnt = getInversionCount(workArr, start, mid)
+ getInversionCount(workArr, mid+1, end);
//...count the inversion count between two part array, when sort them
vector<int> tmpArr(end-start+1);
int i = start;
int j = mid+1;
int k = 0;
while(i <= mid || j <= end)
{
if(i > mid) tmpArr[k++] = workArr[j++];
else if(j > end)
{
inversionCnt += j-mid-1;
tmpArr[k++] = workArr[i++];
}
else
{
if(workArr[i] <= workArr[j])//...= is very important here to make this algorithm right
{
inversionCnt += j-mid-1;
tmpArr[k++] = workArr[i++];
}
else tmpArr[k++] = workArr[j++];
}
}
for(k = 0; k < tmpArr.size(); ++k)
workArr[start+k] = tmpArr[k];
//...return result
return inversionCnt;
}
int solution(const vector<int> &A) {
// write your code in C++98
//...using merge sort like methods to calculate the inversion count
vector<int> workArr = A;
long long ans = getInversionCount(workArr, 0, workArr.size()-1);
if(ans > 1000000000) return -1;
else return (int)ans;
}