Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [−2,1,−3,4,−1,2,1,−5,4],
the contiguous subarray [4,−1,2,1] has the largest sum = 6.
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class Solution {
public:
int maxSubArray(vector<int>& nums) {
int sum = 0, maxx = INT_MIN;
if(nums.size() == 0) return 0;
for(int num : nums) {
sum += num;
if(sum > maxx) maxx = sum;
if(sum < 0) sum = 0;
}
return maxx;
}
};
本文介绍了一种寻找具有最大和的连续子数组的算法实现。通过遍历整数数组并维护一个当前和与最大和变量,该算法能在O(n)的时间复杂度内找到指定条件下的最优解。
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