Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [−2,1,−3,4,−1,2,1,−5,4]
,
the contiguous subarray [4,−1,2,1]
has the largest sum = 6
.
如果当前和为负数,再加也没意义,那么从当前sum=a[i]开始,反正不会再差了。。。。
class Solution {
public:
int maxSubArray(int A[], int n) {
int res=INT_MIN;
int sum=0;
for(int i=0; i<n; i++){
sum<0? sum=A[i]: sum+=A[i];
res=max(sum,res);
}
return res;
}
};