Description
Given a string s and an integer k, return true if you can use all the characters in s to construct k palindrome strings or false otherwise.
Example 1:
Input: s = "annabelle", k = 2
Output: true
Explanation: You can construct two palindromes using all characters in s.
Some possible constructions "anna" + "elble", "anbna" + "elle", "anellena" + "b"
Example 2:
Input: s = "leetcode", k = 3
Output: false
Explanation: It is impossible to construct 3 palindromes using all the characters of s.
Example 3:
Input: s = "true", k = 4
Output: true
Explanation: The only possible solution is to put each character in a separate string.
Constraints:
1 <= s.length <= 10^5
s consists of lowercase English letters.
1 <= k <= 10^5
Solution
To make k
palindromes, we could have at most k
odd characters, go through the string and calculate the count of odd characters, then compare with k
.
One corner case: if k
is larger than the length of the string, we need to return False
Time complexity:
o
(
n
)
o(n)
o(n)
Space complexity:
o
(
n
)
o(n)
o(n)
Code
class Solution:
def canConstruct(self, s: str, k: int) -> bool:
str_cnt = collections.Counter(s)
odd_cnt = 0
for ch, cnt in str_cnt.items():
odd_cnt += (cnt & 1 == 1)
return odd_cnt <= k <= len(s)