[Leetcode] 124. Binary Tree Maximum Path Sum

本文深入探讨了寻找二叉树中最大路径和的算法实现,通过递归辅助函数maxPathSumHelper,巧妙地解决了这一经典问题。示例展示了输入为[1,2,3]和[-10,9,20,null,null,15,7]时的正确输出,分别为6和42。算法不仅考虑了从任意节点到任意节点的路径,还特别指出路径至少包含一个节点,且不强制经过根节点。

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Given a non-empty binary tree, find the maximum path sum.

For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path must contain at least one node and does not need to go through the root.

Example 1:

Input: [1,2,3]

   1
  / \
 2   3

Output: 6
Example 2:

Input: [-10,9,20,null,null,15,7]

-10
/
9 20
/
15 7

Output: 42

class Solution {
public:
    int maxPathSum(TreeNode* root) {    // root != nulllptr
        return maxPathSumHelper(root).first;
    }
private:
    pair<int, int> maxPathSumHelper(TreeNode *root) {
        if (!root) return {INT_MIN, 0};
        
        auto left = maxPathSumHelper(root->left);
        auto right = maxPathSumHelper(root->right);
        left.second = max(left.second, 0);
        right.second = max(right.second, 0);
        
        return {max(max(left.first, right.first),  left.second + right.second + root->val),
                max(left.second, right.second) + root->val};
    }
};
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