LRU Cache - Least Recently Used可以用一个list来实现(front为使用最久远的)
class LRUCache {
public:
LRUCache(int capacity) {
cap = capacity;
}
int get(int key) {
auto it = m.find(key);
if(it==m.end()) return -1;
lru.splice(lru.begin(), lru, it->second);
// m[key] = lru.begin(); no need to do this line
return it->second->second;
}
void put(int key, int value) {
auto it = m.find(key);
if(it!=m.end()) lru.erase(m[key]);
lru.push_front({key, value});
m[key] = lru.begin();
if(m.size()>cap){
m.erase(lru.back().first);
lru.pop_back();
}
}
private:
int cap;
unordered_map<int, list<pair<int,int>>::iterator> m;
list<pair<int,int>> lru;
};
/**
* Your LRUCache object will be instantiated and called as such:
* LRUCache obj = new LRUCache(capacity);
* int param_1 = obj.get(key);
* obj.put(key,value);
*/