WERTYU

最新推荐文章于 2021-02-02 17:20:01 发布

qxq_sunshine

最新推荐文章于 2021-02-02 17:20:01 发布

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分类专栏：算法竞赛入门经典

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本文介绍了一种常见的键盘输入错误——将手放在键盘上错开一行，导致字母错位的问题，并提供了一个简单的C语言程序来解码这种错位输入。输入包含多种字符，程序通过查找和替换的方式实现解码。

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WERTYU

http://acm.hdu.edu.cn/webcontest/contest_showproblem.php?pid=1020&ojid=1&cid=3681&hide=0

Time Limit : 2000/1000ms (Java/Other) Memory Limit : 131072/65536K (Java/Other)

Total Submission(s) : 6 Accepted Submission(s) : 3

Problem Description

A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this manner.

Input

Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except Q, A, Z), or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab, BackSp, Control, etc.] are not represented in the input.

Output

You are to replace each letter or punctuation symbol by the one immediately to its left on the QWERTY keyboard shown above. Spaces in the input should be echoed in the output.

Sample Input

  O S, GOMR YPFSU/
 

Sample Output

  I AM FINE TODAY.
 

代码实现：

//WETYU
#include<stdio.h>
char s[]="`1234567890-=QWERTYUIOP[]ASDFGHJKL;'ZXCVBNM,./";
int main()
{
int i,c;
while((c=getchar())!=EOF)
{
for(i=1;s[i]&&s[i]!=c;i++) ;
if(s[i])
putchar(s[i-1]);
else
putchar(c);
}
return 0;
}

//实现思路很好，特别简单方便