WERTYU（常量数组的妙用）（UVa10082）

最新推荐文章于 2022-09-28 12:54:31 发布

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最新推荐文章于 2022-09-28 12:54:31 发布

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分类专栏： C++基础

本文链接：https://blog.youkuaiyun.com/qq_34041537/article/details/54691527

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本文介绍了一种解决常见键盘输入错误的算法，通过将输入的字符替换为QWERTY键盘布局上左侧的字符来纠正输入。文章提供了一个使用C语言实现的示例程序，该程序能够读取标准输入并输出修正后的文本。

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 WERTYU

 
 
   Time Limit: 1000ms
  
 
   Memory Limit: 65536KB
  This problem will be judged on 
 PKU. Original ID: 
 2538
 
 64-bit integer IO format: 
 %lld      Java class name: 
 Main
 
 
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 A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this manner. 
  
 
 Input 

  Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except Q, A, Z), or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab, BackSp, Control, etc.] are not represented in the input. 
  
 
 Output 

  You are to replace each letter or punctuation symbol by the one immediately to its left on the QWERTY keyboard shown above. Spaces in the input should be echoed in the output. 
 
 
  
 
 Sample Input 
O S, GOMR YPFSU/

Sample Output

I AM FINE TODAY.

Source

Waterloo local 2001.01.27

代码分析：常量数组的妙用

#include<stdio.h>

char s[] = "`1234567890-=QWERTYUIOP[]\\ASDFGHJKL;'ZXCVBNM,./";

int main()
{
	int i,c;
	while((c =getchar()) != EOF)
	{
		for(i = 0; s[i] && s[i]!=c; i++);
		if(s[i]) printf("%c",s[i-1]);
		else printf("%c",c);
		
	}
	
	return 0;
}