class Solution {
public:
bool isValidBST(TreeNode* root) {
return dfs(root, LONG_MIN, LONG_MAX);
/*if (root == NULL)return true;
if (root->left->val >= root->val||root->val >= root->right->val)
return false;
return isValidBST(root->left)&&isValidBST(root->right);*/
}
bool dfs(TreeNode*root, long mi,long ma) {
if (!root )return true;
if (root->val < mi || root->val > ma)return false;
return dfs(root->left, mi, root->val-1ll) && dfs(root->right, root->val+1ll, ma);//+-1LLlonglong防止数据溢出
}
};
leetcode 98. 验证二叉搜索树(边界细节处理防止溢出)
最新推荐文章于 2021-08-10 09:37:27 发布