2024: The Famous Clock

本文介绍了一个简单的C语言程序,用于将钟表上的罗马数字转换为对应的阿拉伯数字。该程序适用于1到12之间的整数,并使用字符串比较来确定输入的罗马数字所对应的数值。

 

时间限制: 1 Sec  内存限制: 64 MB
提交: 60  解决: 29
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题目描述

Mr. B, Mr. G and Mr. M are now in Warsaw, Poland, for the 2012’s ACM-ICPC World Finals Contest. They’ve decided to take a 5 hours training every day before the contest. Also, they plan to start training at 10:00 each day since the World Final Contest will do so. The scenery in Warsaw is so attractive that Mr. B would always like to take a walk outside for a while after breakfast. However, Mr. B have to go back before training starts, otherwise his teammates will be annoyed. Here is a problem: Mr. B does not have a watch. In order to know the exact time, he has bought a new watch in Warsaw, but all the numbers on that watch are represented in Roman Numerals. Mr. B cannot understand such kind of numbers. Can you translate for him?

输入

Each test case contains a single line indicating a Roman Numerals that to be translated. All the numbers can be found on clocks. That is, each number in the input represents an integer between 1 and 12. Roman Numerals are expressed by strings consisting of uppercase ‘I’, ‘V’ and ‘X’. See the sample input for further information.

输出

For each test case, display a single line containing a decimal number corresponding to the given Roman Numerals.

输入罗马数字,输出对应阿拉伯数字

代码:

#include <stdio.h>
#include<string.h>
int main()
{
    char c[13][6]={"0","I","II","III","IV","V","VI","VII","VIII","IX","X","XI","XII"};
    char a[6];int i,cas=1;
    while(~scanf("%s",a))
    {
        for(i=1;i<=12;i++)
        if(strcmp(c[i],a)==0)
        printf("Case %d: %d\n",cas++,i); //此处必须用cas++,若用i则不能通过,真无趣。
    }
    return 0;
    
}

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