The Famous Clock

本文介绍了一款帮助用户将罗马数字转换为十进制数的程序,适用于ACM-ICPC世界总决赛前的训练时间管理场景。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

The Famous Clock

时间限制: 1000 ms  |  内存限制: 65535 KB
难度: 1
描述

Mr. B, Mr. G and Mr. M are now in Warsaw, Poland, for the 2012’s ACM-ICPC World Finals Contest. They’ve decided to take a 5 hours training every day before the contest. Also, they plan to start training at 10:00 each day since the World Final Contest will do so. The scenery in Warsaw is so attractive that Mr. B would always like to take a walk outside for a while after breakfast. However, Mr. B have to go back before training starts, otherwise his teammates will be annoyed. Here is a problem: Mr. B does not have a watch. In order to know the exact time, he has bought a new watch in Warsaw, but all the numbers on that watch are represented in Roman Numerals. Mr. B cannot understand such kind of numbers. Can you translate for him?

输入
Each test case contains a single line indicating a Roman Numerals that to be translated. All the numbers can be found on clocks. That is, each number in the input represents an integer between 1 and 12. Roman Numerals are expressed by strings consisting of uppercase ‘I’, ‘V’ and ‘X’. See the sample input for further information.
输出
For each test case, display a single line containing a decimal number corresponding to the given Roman Numerals.
样例输入
I
II
III
IV
V
VI
VII
VIII
IX
X
XI
XII
样例输出
Case 1: 1
Case 2: 2
Case 3: 3
Case 4: 4
Case 5: 5
Case 6: 6
Case 7: 7
Case 8: 8
Case 9: 9
Case 10: 10
Case 11: 11
Case 12: 12

查看代码---运行号:252406----结果:Accepted

运行时间: 2012-10-05 19:47:00  |  运行人: huangyibiao
01. #include <string>
02. #include <iostream>
03. usingnamespace std;
04.  
05. intmain()
06. {
07. string s;
08. intcount = 0;
09. while(cin >> s)
10. {
11. cout <<"Case " << ++count  << ": ";
12. if(s == "I")
13. cout <<"1\n";
14. elseif (s == "II")
15. cout <<"2\n";
16. elseif (s == "III")
17. cout <<"3\n";
18. elseif (s == "IV")
19. cout <<"4\n";
20. elseif (s == "V")
21. cout <<"5\n";
22. elseif (s == "VI")
23. cout <<"6\n";
24. elseif (s == "VII")
25. cout <<"7\n";
26. elseif (s == "VIII")
27. cout <<"8\n";
28. elseif (s == "IX")
29. cout <<"9\n";
30. elseif (s == "X")
31. cout <<"10\n";
32. elseif (s == "XI")
33. cout <<"11\n";
34. elseif (s == "XII")
35. cout <<"12\n";
36. }
37. return0;
38. }

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值