PAT乙级(Basic Level)真题之数字分类-优快云博客

本文链接：https://blog.youkuaiyun.com/qq_41458842/article/details/89392601

本文介绍了一个Java程序，用于从用户输入的整数数组中统计并分析特定数值特征：包括被5整除且为偶数的总和、被5除余1的数的交替累加、被5除余2的数的计数、被5除余3的数的平均值以及被5除余4的最大值。通过一系列条件判断和数学运算，该程序提供了对输入数据集的深入洞察。

package x;
import java.util.Scanner;

public class z {
   public static void main(String[] args) {
       Scanner s = new Scanner(System.in);
       int A1=0;
       int A2=0;
       int A3=0;
       double A4=0.0;
       int A5=0;
       int a = s.nextInt();
       int temp = 1;//记录被5整除余1数的顺序
       int temp2 = 0;//记录被5整除余3数的个数
       int max = 0;
       int sum = 0;
       int[] num = new int[a];
       for(int i=0;i<a;i++){
           num[i] = s.nextInt();
       }

       for(int i=0;i<a;i++){
           if((num[i]%2)==0&&(num[i]%5==0)) {
               A1+=num[i];
           }

           if((num[i]%5==1)) {
               if((temp%2)==1){
                   A2+=num[i];
               }
               else
                   A2-=num[i];
               temp++;
           }

           if((num[i]%5==2)){
               A3++;
           }

           if((num[i]%5==3)) {
               temp2++;
               sum+=num[i];
           }

           if((num[i]%5==4)) {
               if(num[i]>max) {
                   max = num[i];
               }
           }

       }
       A4 = (double)sum /temp2;
       A5 = max;
       if(A1==0){
           System.out.print("N ");
       }
       else
           System.out.print(A1+" ");

       if(A2==0){
           System.out.print("N ");
       }
       else
           System.out.print(A2+" ");


       if(A3==0){
           System.out.print("N ");
       }
       else
           System.out.print(A3+" ");


       if(temp2==0){
           System.out.print("N ");
       }
       else
           System.out.print(String.format("%.1f",A4)+" ");

       if(A5==0){
           System.out.print("N");
       }
       else
           System.out.print(A5);