PAT (Advanced Level) Practice 1001 A+B Format（20 分）C语言

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最新推荐文章于 2024-09-04 16:30:41 发布

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本文详细解析了1001A+BFormat题目，介绍了如何计算两个整数的和并按照标准格式输出结果，包括使用逗号进行千位分隔的细节。提供了完整的C语言代码实现，适合初学者学习和理解格式化输出的方法。

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1001 A+B Format（20 分）

Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

C

#include<stdio.h>
int main() {
	int a,b,sum,m;
	scanf("%d %d",&a,&b);
	sum=a+b;
	if(sum<0)
		m=-sum;
	else
		m=sum;
	if(m>=1000||m<=-1000) {
		if(m>=1000000||m<=-1000000) {
			printf("%d",sum/1000000);
			printf(",");
			if((m/1000)%1000>=100)
				printf("%d",(m/1000)%1000);
			else if((m/1000)%1000>=10)
				printf("0%d",(m/1000)%1000);
			else if((m/1000)%1000>=0)
				printf("00%d",(m/1000)%1000);
			printf(",");
		} else {
			printf("%d",sum/1000);
			printf(",");
		}
		if(m%1000>=100)
			printf("%d",m%1000);
		else if(m%1000>=10)
			printf("0%d",m%1000);
		else if(m%1000>=0)
			printf("00%d",m%1000);
	} else {
		printf("%d",sum);
	}
	return 0;
}