【PAT甲级】1001 A+B Format （20 分）

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本文介绍了一个C++程序，用于计算两个整数a和b的和，并以标准格式输出结果，即每三位数字间插入一个逗号，适用于正负10^6范围内的整数运算。

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Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

翻译：输入a,b,范围都在正负10^6内，计算a + b，并且用标准格式输出，即，每隔三位输出一个逗号。

#include <iostream>
#include <string>
#include <cmath> 
#include <algorithm>
using namespace std;
int main(){
	int a,b,c;
	string ans = "";
	cin>>a>>b;
	c = a + b;
	if(c < 0){
		cout<<"-";
		c = c + 2*abs(c);
	}
	if(c == 0){cout<<"0"<<endl; return 0;}
	while(c > 0){
		int t = c % 10;
		ans += (char)t + '0';
		c = c / 10;
	} 
	reverse(ans.begin(),ans.end());
	int len = ans.length();
	for(int i = len - 1; i >= 0; i--){
		if((i + 1) % 3 == 0 && (i + 1) != len) cout<<",";
		cout<<ans[len - i - 1];
	}
	return 0;
}