python 笔记 if语句的简单嵌套 《笨办法学Python》习题31 ——1.3

习题 31: 作出决定

目标与感悟：

•符号不能混用，制表符和4个空格两者只能同时使用一个（同一种功能时）。

•知晓if语句的使用，理论上可以无限嵌套。

•嵌套，我理解就跟树的分支一样。

•if语句只返回为Ture的第一个区块，如果一直没有符合的将会结束操作，所以，想法一定要完善。

 

ex31.py

#-*- coding:utf-8-*-
print "You enter a dark room with two doors. Do you go throuth door #1 or door #2?"
 
door = raw_input("> ")
 
if door == "1":
	print "There's a giant bear here eating a cheese cake. What do you do?"
	print "1. Take the cake."
	print "2. Scream at the bear."
	bear = raw_input("> ")
 
    if bear == "1":
		print "The bear eats your face off. Good job!"
	elif bear == "2":
		print "The bear eats your legs off. Good job!"
	else:
	print "Well, doing %s is probably better. Bear runs away." %bear
elif door == "2":
	print "You stare into the endless abyss at Cthulhu's retina."
	print "1. Blueberries."
	print "2. Yellow jacket clothespins."
	print "3. Understanding revolvers yelling melodies."
	insanity = raw_input("> ")
	if insanity == "1" or insanity == "2":
		print "Your body survives powered by a mind of jello. Good job!"
	else:
		print "The insanity rots your eyes into a pool of muck. Good job!"
else:
	print "You stumble around and fall on a knife and die. Good job!"

运行结果:

很奇怪,出错了`````````````

看语法结构什么的好像也没什么问题,报错的内容即缩进对应级别不匹配,就是可能多加了什么括号之类.

后来打开notepad显示空格和制表符

看起来都是4个空格距离,但符号不一样就是不一样,应该是制表符(TAB键)，修改完毕后则正常了。

正确输出结果：

ex31.py

下面测试一个简单三层嵌套：

ex31_1.py

#-*- coding:utf-8-*-
 
print "Enter one number (1-10),please."
 
a = raw_input("> ")
if a == "1":
	print "1. Take the cake."
	print "2. ET is very interesting!"
	print "3. Scream at the bear."
	b = raw_input("> ")
	if b == "1":
		print "Yeah ,cake is vert delicious!What kind of cake do you like?"
		print "1. apple cake."
		print "2. banana cake."
		print "3. orange cake."
		c = raw_input("> ")
		if c == "1":
			print "Yeah,apple cake is vert delicious!"
 
else:
	print "You stumble around and fall on a knife and die. Good job!"

运行结果: