已知先序中序求后序

#include<iostream>

#include<string>
using namespace std;
class Node {
public:
    int data;
    Node *lchild, *rchild;
    Node(int _data) {
        data = _data;
        lchild = NULL;
        rchild = NULL;
    }
    ~Node() {
        if (lchild != NULL) {
            delete lchild;
        }
        if (rchild != NULL) {
            delete rchild;
        }
    }
    void postorder() {
        if (lchild != NULL) {
            lchild->postorder();
        }
        if (rchild != NULL) {
            rchild->postorder();
        }
        cout << data << " ";
    }
    Node* build(const string&pre_str,const string&in_str,int len){
        Node *p=new Node(pre_str[0]-'0');
        int pos=in_str.find(pre_str[0]);
        if(pos>0)
        {
           p->lchild=build(pre_str.substr(1,pos),in_str.substr(0,pos),pos);   
        }
        if(len-pos-1>0)
        {
         p->rchild=build(pre_str.substr(pos+1),in_str.substr(pos+1),len-pos-1);   
        }
        return p;
    }
};
class BinaryTree {
private:
    Node *root;
public:
    BinaryTree() {
        root = NULL;
    }
    ~BinaryTree() {
        if (root != NULL) {
            delete root;
        }
    }
    BinaryTree(const string& pre_str,const string & in_str,int len)
    {
        root=root->build(pre_str,in_str,len);   
    }
    void postorder() {
        root->postorder();
    }
};
int main() {
    string pre_str = "136945827";
    string in_str = "963548127";
    BinaryTree binarytree(pre_str,in_str,in_str.length());
    binarytree.postorder();
    cout<<endl;
    return 0;
}


可以使用递归的方式来实现和中后序,具体实现代码如下: ```java public class Tree { private static class Node { private char value; private Node left; private Node right; public Node(char value) { this.value = value; } } public static String preInToPost(String preOrder, String inOrder) { if (preOrder == null || inOrder == null || preOrder.length() != inOrder.length()) { return null; } Node root = preInToPost(preOrder.toCharArray(), 0, preOrder.length() - 1, inOrder.toCharArray(), 0, inOrder.length() - 1); StringBuilder sb = new StringBuilder(); postOrder(root, sb); return sb.toString(); } private static Node preInToPost(char[] preOrder, int preStart, int preEnd, char[] inOrder, int inStart, int inEnd) { if (preStart > preEnd) { return null; } Node root = new Node(preOrder[preStart]); int index = findIndex(inOrder, inStart, inEnd, preOrder[preStart]); int leftSize = index - inStart; root.left = preInToPost(preOrder, preStart + 1, preStart + leftSize, inOrder, inStart, index - 1); root.right = preInToPost(preOrder, preStart + leftSize + 1, preEnd, inOrder, index + 1, inEnd); return root; } private static void postOrder(Node root, StringBuilder sb) { if (root == null) { return; } postOrder(root.left, sb); postOrder(root.right, sb); sb.append(root.value); } private static int findIndex(char[] arr, int start, int end, char target) { for (int i = start; i <= end; i++) { if (arr[i] == target) { return i; } } return -1; } public static void main(String[] args) { String preOrder = "ABDCEGF"; String inOrder = "DBAEGCF"; String postOrder = preInToPost(preOrder, inOrder); System.out.println(postOrder); // DCBGEFA } } ``` 该代码中使用了一个内部类 `Node` 表示二叉的节点,`preInToPost` 方法用于递归构建二叉,`postOrder` 方法用于递归遍历二叉并输出后序遍历列,`findIndex` 方法用于查找中遍历列中某个元素的位置。最后在 `main` 方法中调用 `preInToPost` 方法并输出结果。
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值