258. Add Digits
Total Accepted:
74723 Total Submissions:
155249 Difficulty: Easy
Given a non-negative integer num
, repeatedly add all its digits until the result has only one digit.
For example:
Given num = 38
, the process is like: 3 + 8 = 11
,
1 + 1 = 2
. Since 2
has only one digit, return it.
Follow up:
Could you do it without any loop/recursion in O(1) runtime?
class Solution {
public:
int addDigits(int num) {
return 1 + (num - 1) % 9;
}
};