PAT甲级 1058 A+B in Hogwarts （20 分）水题

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根据哈利波特系列中描述的魔法货币系统，本题要求编程实现两个魔法货币的加法运算。货币单位包括Galleon（金加隆）、Sickle（银西可）和Knut（铜纳特），其换算比例为17个Sickle等于1个Galleon，29个Knut等于1个Sickle。示例代码展示了如何读取标准格式的两个魔法货币并计算它们的总和。

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1058 A+B in Hogwarts （20 分）

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

题目大意：17个Sickle对换一个Galleon，29个Knut对换一个Sickle。根据Galleon.Sickle.Knut的方式相加A和B

#include<iostream>
#include<algorithm>
using namespace std;

int main(){
	int a,b,c;//第一个输入 
	int d,e,f;//第二个输入 
	int g,h,i;//结果 
	scanf("%d.%d.%d %d.%d.%d",&a,&b,&c,&d,&e,&f);
	
	int flag = 0;
	i = c+f;
	if(i >= 29){
		i -= 29;
		flag = 1;
	}
			
	h = b+e+flag;
	flag = 0;
	if(h >= 17){
		h -= 17;
		flag = 1;
	}
	
	g = a+d+flag;
	printf("%d.%d.%d",g,h,i);
		
	return 0;
}