Python惰性计算计算圆周率值

import random
import time
import numpy as np


def a(n):
    count = 0
    j = 0
    start_time = time.perf_counter()
    for i in range(1, n + 1):

        x = random.uniform(-1, 1)
        y = random.uniform(-1, 1)

        if pow(x * x + y * y, 0.5) <= 1:
            count += 1
        j += 1
        end_time = time.perf_counter()
        print("{:^10}".format(i), end="    ")
        print("运行时间为{:.4f}s".format(end_time - start_time), end="    ")
        print("误差为{:<8.3%}".format((np.pi - count * 4 / j)/np.pi),end="    ")
        yield count * 4 / j


n = eval(input())
for i in a(n):
    print("拟合值为{:.4f}".format(i))

输出：这里输入的n为10

    1         运行时间为0.0000s    误差为-27.324%    拟合值为4.0000
    2         运行时间为0.0001s    误差为-27.324%    拟合值为4.0000
    3         运行时间为0.0001s    误差为-27.324%    拟合值为4.0000
    4