读入一个自然数n,计算其各位数字之和,用汉语拼音写出和的每一位数字。
输入格式:每个测试输入包含1个测试用例,即给出自然数n的值。这里保证n小于10100。
输出格式:在一行内输出n的各位数字之和的每一位,拼音数字间有1 空格,但一行中最后一个拼音数字后没有空格。
输入样例:
1234567890987654321123456789
输出样例:
yi san wu
#include <iostream>
#include <string.h>
using namespace std;
#define maxn 101
int main(){
char c[maxn];
int a[maxn],b[5];
int sum=0,t=0;
gets(c);
for (int i = 0; i < strlen(c); i++)
{
a[i]=(int)(c[i]-48);
}
for (int i = 0; i < strlen(c); i++)
{
sum+=a[i];
}
while (sum!=0)
{
b[t] = sum%10;
sum = sum/10;
++t;
}
switch (b[t-1])
{
case 0:cout<<"ling";break;
case 1:cout<<"yi";break;
case 2:cout<<"er";break;
case 3:cout<<"san";break;
case 4:cout<<"si";break;
case 5:cout<<"wu";break;
case 6:cout<<"liu";break;
case 7:cout<<"qi";break;
case 8:cout<<"ba";break;
case 9:cout<<"jiu";break;
default:
break;
}
for (int i = t-2; i >= 0; i--)
{
switch (b[i])
{
case 0:cout<<" "<<"ling";break;
case 1:cout<<" "<<"yi";break;
case 2:cout<<" "<<"er";break;
case 3:cout<<" "<<"san";break;
case 4:cout<<" "<<"si";break;
case 5:cout<<" "<<"wu";break;
case 6:cout<<" "<<"liu";break;
case 7:cout<<" "<<"qi";break;
case 8:cout<<" "<<"ba";break;
case 9:cout<<" "<<"jiu";break;
default:
break;
}
}
return 0;
}