leetcode 198 house robber

最新推荐文章于 2020-09-14 21:10:02 发布

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最新推荐文章于 2020-09-14 21:10:02 发布

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本文介绍了一种解决特定抢劫问题的方法，即在一个街区中选择最优的房屋进行抢劫以获得最大金额，同时避免触发相邻房屋的安全警报。通过动态规划算法实现了这一目标，并给出了具体的代码实现。

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题目描述：

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.

Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.

Example 1:

Input: [1,2,3,1]
Output: 4
Explanation: Rob house 1 (money = 1) and then rob house 3 (money = 3).
             Total amount you can rob = 1 + 3 = 4.

Example 2:

Input: [2,7,9,3,1]
Output: 12
Explanation: Rob house 1 (money = 2), rob house 3 (money = 9) and rob house 5 (money = 1).
             Total amount you can rob = 2 + 9 + 1 = 12.

实现：

class Solution {
    public int rob(int[] nums) {
        if(nums==null||nums.length==0){
            return 0;
        }
        if(nums.length==1){
            return nums[0];
        }
        if(nums.length==2){
            return Math.max(nums[0],nums[1]);
        }
        int[] dp=new int[nums.length];
        dp[0]=nums[0];
        dp[1]=Math.max(nums[0],nums[1]);
        for(int i=2;i<nums.length;i++){
            dp[i]=Math.max(dp[i-1],dp[i-2]+nums[i]);
        }
        return dp[nums.length-1];        
    }
}