java http 发请求，结果转jsonobject解析

HTTP请求与JSON解析示例

最新推荐文章于 2023-05-30 21:50:18 发布

nx188

最新推荐文章于 2023-05-30 21:50:18 发布

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文章标签： java

本文链接：https://blog.youkuaiyun.com/nx188/article/details/49536489

本文演示了如何使用Java进行HTTP请求，并解析JSON对象获取特定字段值。


import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URL;
import java.net.URLConnection;
import java.util.List;
import java.util.Map;

import org.json.JSONException;
import org.json.JSONObject;

public class httprequest {

	public static void main(String[] args) throws IOException, JSONException {
		//http 请求
		String urlstr = "https://www.baidu.com";
		String result = "";
		BufferedReader br = null;
		URL url = new URL(urlstr);
		URLConnection connection = url.openConnection();
		connection.setRequestProperty("accept", "*/*");
        connection.setRequestProperty("connection", "Keep-Alive");
        connection.setRequestProperty("user-agent",
                 "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1;SV1)");
        connection.connect();
        Map<String,List<String>> map = connection.getHeaderFields();
        for(String key:map.keySet()){
        	 System.out.println(key+map.get(key));
        }
        br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
        String line = null;
        while((line = br.readLine())!=null){
        	 result+=line;
        }
        System.out.println("-----------------\n"+result);
        //解析jsonobject
        String jsonstr = "{\"语文\":\"99\",\"数学\":\"98\",\"英语\":\"97\"}";
        String value1 = null;
        JSONObject jsonobj = new JSONObject(jsonstr);
        value1 = jsonobj.getString("数学");
        System.out.println(value1);
	}

}