Floyd+ 二分+最大流
vj挂了,不知道对不对
#include<iostream>
#include<string>
#include<cstring>
#include<algorithm>
#include<cstdio>
#include<vector>
#include<queue>
using namespace std;
#define mem(a,b) memset(a,b,sizeof(a));
#define sf scanf
#define pf printf
#define LL long long
#define bug1 cout<<"bug1"<<endl;
#define bug2 cout<<"bug2"<<endl;
#define bug3 cout<<"bug3"<<endl;
#define mem(a,b) memset(a,b,sizeof(a));
#define inf 0x3f3f3f3f
const int maxn=2205;
const int INF=1e9+5;
struct Edge {
int from, to, cap, flow;
};
bool operator < (const Edge& a, const Edge& b) {
return a.from < b.from || (a.from == b.from && a.to < b.to);
}
struct Dinic {
int n, m, s, t;
vector<Edge> edges;
vector<int> G[maxn];
bool vis[maxn];
int d[maxn];
int cur[maxn];
void init(int n) {
for(int i = 0; i < n; i++) G[i].clear();
edges.clear();
}
void ClearFlow() {
for(int i = 0; i < edges.size(); i++) edges[i].flow = 0;
}
void addedge(int from, int to, int cap) {
edges.push_back((Edge){from, to, cap, 0});
edges.push_back((Edge){to, from, 0, 0});
m = edges.size();
G[from].push_back(m-2);
G[to].push_back(m-1);
}
bool BFS() {
memset(vis, 0, sizeof(vis));
queue<int> Q;
Q.push(s);
vis[s] = 1;
d[s] = 0;
while(!Q.empty()) {
int x = Q.front(); Q.pop();
for(int i = 0; i < G[x].size(); i++) {
Edge& e = edges[G[x][i]];
if(!vis[e.to] && e.cap > e.flow) {
vis[e.to] = 1;
d[e.to] = d[x] + 1;
Q.push(e.to);
}
}
}
return vis[t];
}
int DFS(int x, int a) {
if(x == t || a == 0) return a;
int flow = 0, f;
for(int& i = cur[x]; i < G[x].size(); i++) {
Edge& e = edges[G[x][i]];
if(d[x] + 1 == d[e.to] && (f = DFS(e.to, min(a, e.cap-e.flow))) > 0) {
e.flow += f;
edges[G[x][i]^1].flow -= f;
flow += f;
a -= f;
if(a == 0) break;
}
}
return flow;
}
int maxflow(int s, int t) {
this->s = s; this->t = t;
int flow = 0;
while(BFS()) {
memset(cur, 0, sizeof(cur));
flow += DFS(s, INF);
}
return flow;
}
vector<int> Mincut() {
vector<int> ans;
for(int i = 0; i < edges.size(); i++) {
Edge& e = edges[i];
if(vis[e.from] && !vis[e.to] && e.cap > 0) ans.push_back(i);
}
return ans;
}
void Reduce() {
for(int i = 0; i < edges.size(); i++) edges[i].cap -= edges[i].flow;
}
};
Dinic g;
int f,p;
int d[maxn][maxn];
struct OP{
int c,d;
}op[maxn];
int main(){
//OP op[maxn];
while(~sf("%d%d",&f,&p)){
int s=0,t=2*f+1;
g.init(t+1);
int sum=0;
for(int i=1;i<=f;++i){
int a,b;
sf("%d%d",&a,&b);
op[i].c=a;op[i].d=b;
//cout<<op[i].c<<' '<<op[i].d<<endl;//怎么回事。。居然输出不了。。
sum+=a;
}
mem(d,inf);
for(int i=1;i<=p;++i){
int a,b,c;
sf("%d%d%d",&a,&b,&c);
if(d[a][b]>c){
d[a][b]=d[b][a]=c;
}
}
for(int k=1;k<=f;++k){
for(int i=1;i<=f;++i){
for(int j=1;j<=f;++j){
if(i==j)d[i][j]=0;
d[i][j]=min(d[i][j],d[i][k]+d[k][j]);
}
}
}
int l=0,r=INF;
while(l<r){
int mid=(l+r)>>1;
g.init(t+1);
for(int i=1;i<=f;++i){
g.addedge(s,i,op[i].c);
g.addedge(i,i+f,op[i].d);
g.addedge(i+f,t,op[i].d);
}
for(int i=1;i<=f;++i){
for(int j=1;j<=f;++j){
if(d[i][j]<=mid){
g.addedge(i,j+f,INF);
}
}
}
int tmp=g.maxflow(s,t);
if(tmp==sum)r=mid;
else l=mid+1;
}
pf("%d\n",r);
}
}
#include<iostream>
#include<string>
#include<cstring>
#include<algorithm>
#include<cstdio>
#include<vector>
#include<queue>
using namespace std;
#define mem(a,b) memset(a,b,sizeof(a));
#define sf scanf
#define pf printf
#define LL long long
#define bug1 cout<<"bug1"<<endl;
#define bug2 cout<<"bug2"<<endl;
#define bug3 cout<<"bug3"<<endl;
#define mem(a,b) memset(a,b,sizeof(a));
#define inf 0x3f3f3f3f
const int maxn=2205;
const int INF=1e9+5;
struct Edge {
int from, to, cap, flow;
};
bool operator < (const Edge& a, const Edge& b) {
return a.from < b.from || (a.from == b.from && a.to < b.to);
}
struct Dinic {
int n, m, s, t;
vector<Edge> edges;
vector<int> G[maxn];
bool vis[maxn];
int d[maxn];
int cur[maxn];
void init(int n) {
for(int i = 0; i < n; i++) G[i].clear();
edges.clear();
}
void ClearFlow() {
for(int i = 0; i < edges.size(); i++) edges[i].flow = 0;
}
void addedge(int from, int to, int cap) {
edges.push_back((Edge){from, to, cap, 0});
edges.push_back((Edge){to, from, 0, 0});
m = edges.size();
G[from].push_back(m-2);
G[to].push_back(m-1);
}
bool BFS() {
memset(vis, 0, sizeof(vis));
queue<int> Q;
Q.push(s);
vis[s] = 1;
d[s] = 0;
while(!Q.empty()) {
int x = Q.front(); Q.pop();
for(int i = 0; i < G[x].size(); i++) {
Edge& e = edges[G[x][i]];
if(!vis[e.to] && e.cap > e.flow) {
vis[e.to] = 1;
d[e.to] = d[x] + 1;
Q.push(e.to);
}
}
}
return vis[t];
}
int DFS(int x, int a) {
if(x == t || a == 0) return a;
int flow = 0, f;
for(int& i = cur[x]; i < G[x].size(); i++) {
Edge& e = edges[G[x][i]];
if(d[x] + 1 == d[e.to] && (f = DFS(e.to, min(a, e.cap-e.flow))) > 0) {
e.flow += f;
edges[G[x][i]^1].flow -= f;
flow += f;
a -= f;
if(a == 0) break;
}
}
return flow;
}
int maxflow(int s, int t) {
this->s = s; this->t = t;
int flow = 0;
while(BFS()) {
memset(cur, 0, sizeof(cur));
flow += DFS(s, INF);
}
return flow;
}
vector<int> Mincut() {
vector<int> ans;
for(int i = 0; i < edges.size(); i++) {
Edge& e = edges[i];
if(vis[e.from] && !vis[e.to] && e.cap > 0) ans.push_back(i);
}
return ans;
}
void Reduce() {
for(int i = 0; i < edges.size(); i++) edges[i].cap -= edges[i].flow;
}
};
Dinic g;
int f,p;
int d[maxn][maxn];
struct OP{
int c,d;
}op[maxn];
int main(){
//OP op[maxn];
while(~sf("%d%d",&f,&p)){
int s=0,t=2*f+1;
g.init(t+1);
int sum=0;
for(int i=1;i<=f;++i){
int a,b;
sf("%d%d",&a,&b);
op[i].c=a;op[i].d=b;
//cout<<op[i].c<<' '<<op[i].d<<endl;//怎么回事。。居然输出不了。。
sum+=a;
}
mem(d,inf);
for(int i=1;i<=p;++i){
int a,b,c;
sf("%d%d%d",&a,&b,&c);
if(d[a][b]>c){
d[a][b]=d[b][a]=c;
}
}
for(int k=1;k<=f;++k){
for(int i=1;i<=f;++i){
for(int j=1;j<=f;++j){
if(i==j)d[i][j]=0;
d[i][j]=min(d[i][j],d[i][k]+d[k][j]);
}
}
}
int l=0,r=INF;
while(l<r){
int mid=(l+r)>>1;
g.init(t+1);
for(int i=1;i<=f;++i){
g.addedge(s,i,op[i].c);
g.addedge(i,i+f,op[i].d);
g.addedge(i+f,t,op[i].d);
}
for(int i=1;i<=f;++i){
for(int j=1;j<=f;++j){
if(d[i][j]<=mid){
g.addedge(i,j+f,INF);
}
}
}
int tmp=g.maxflow(s,t);
if(tmp==sum)r=mid;
else l=mid+1;
}
pf("%d\n",r);
}
}
本文介绍了一种结合Floyd算法、二分查找及最大流算法的综合应用案例,通过解决一个具体的流量分配问题来展示这些算法如何协同工作。文中详细解释了如何构造图模型、进行最短路径计算、以及如何使用Dinic算法求解最大流等问题。
1379

被折叠的 条评论
为什么被折叠?



