数组中a与&a的区别

代码

int main()
{
    int a[5]={1,2,3,4,5}; 
    int *ptr=(int *)(&a+1); 
    printf("%d,%d",*(a+1),*(ptr-1)); 
    return 0 ;
}

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结果:

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分析

(a+1)我们都知道,(a+1)=&a[1] , *(a+1) = a[1] ,这个1代表的是sizeof(int)

但是(&a+1)中的1代表的是sizeof(a)

int main()
{
    int a[5]={1,2,3,4,5}; 
    int *ptr=(int *)(&a+1); 

    printf("sizeof(a) =  %d\n",sizeof(a));
    printf("sizeof(&a) = %d\n",sizeof(&a));
    printf("\n\n");

    //输出地址值,a与&a的值是一样的,但含义不同
    printf("&a = %d\n",&a);
    printf("&a+1 = %d\n",(&a+1)) ;
    printf("\n\n");

    printf("a = %d\n",a);
    printf("a+1 = %d \n",a+1);
    printf("\n\n");

    printf("%d,%d",*(a+1),*(ptr-1)); 

  return 0 ;
}