UVa 10070 - Leap Year or Not Leap Year and ...

题目：判断一年是不是闰年，huluculu以及buluculu。

分析：模拟，大数。直接按照提议判断即可。注意题目给出的年限很大，要用高精度运算。

说明：注意buluculu的前提是闰年，什么都不是输出ordinary。 

#include <iostream>
#include <cstdlib>
#include <cstring>
#include <cstdio>

using namespace std;

char year[100000];
int  numb[100000];

int cdiv( int m )
{
	int l = strlen(year)-1;
	for ( int i = 0 ; i <= l ; ++ i )
		numb[i] = year[i]-'0';
	for ( int i = 0 ; i < l ; ++ i ) 
		numb[i+1] += numb[i]%m*10;
	return (numb[l]%m == 0);
}

int main()
{
	int flag;
	while ( cin >> year ) {
		flag = 0;
		if ( cdiv(400) || cdiv(4) && !cdiv(100) ) {
			printf("This is leap year.\n");
			flag += 1;
		}
		if ( cdiv(15) ) {
			printf("This is huluculu festival year.\n");
			flag += 2;
		}
		if ( flag%2 && cdiv(55) )
			printf("This is bulukulu festival year.\n");
		if ( !flag )
			printf("This is an ordinary year.\n");
		printf("\n");
	}
	return 0;
}