Given a linked list, return the node where the cycle begins. If there is no cycle, return null
.
Follow up:
Can you solve it without using extra space?
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode detectCycle(ListNode head) {
if(head==null||head.next==null) return null;
ListNode p=head;
ListNode q=head;
while(q!=null){
p=p.next;
if(q.next!=null) q=q.next.next;
else return null;
if(p==q) break;
}
if(q==null) return null;
p=head;
while(p!=q){
p=p.next;
q=q.next;
}
return p;
}
}